<u>ANSWER</u>
It is not one-to-one function
<u>EXPLANATION</u>
A one-to-one function must pass the horizontal line test.
The graph described in the question looks like the one in the attachment.
A horizontal line drawn in red cuts the graph at more than one point.
Therefore the parabola shown facing up with a vertex
is not a one-to-one function.
A = 4,
we denote one side of the rectangle with
a
, and the other with
b
we can write, that:
a
⋅
b
=
16
so we can write, that
b
=
16
a
Now we can write perimeter
P
as a function of
a
P
=
2
⋅
(
a
+
16
a
)
We are looking for the smallest perimeter, so we have to calculate derivative:
P
(
a
)
=
2
a
+
32
a
P
'
(
a
)
=
2
+
(
−
32
a
2
)
P
'
(
a
)
=
2
−
32
a
2
=
2
a
2
−
32
a
2
The extreme values can only be found in points where
P
'
(
a
)
=
0
P
'
(
a
)
=
0
⇔
2
a
2
−
32
=
0
2
a
2
−
32
=
0
x
a
2
−
16
=
0
×
x
.
.
a
2
=
16
×
×
x
a
=
−
4
or
a
=
4
Since, length is a scalar quantity, therefore, it cannot be negative,
When
a
=
4
,
b
=
16
4
b
=
4
Answer:
A. FALSE
B. TRUE
C. FALSE
D. NOT POSSIBLE TO DETERMINE
Step-by-step explanation:
(A) FALSE. since the power series ∑
has radius of convergence |-4|=4 ans 7> 4 which is beyond its radius of convergence. thus by the theorem of power series, the series diverges at 10.
(B)TRUE. since the radius of convergence of the power series ∑
must be at least |-4| = 4 and 3 lies within this radius, thus it converges at x=3
(C)FALSE the series does not diverge at x=1, since 1 is within its radius of convergence |-4| = 4
(D)NOT POSSIBLE TO DETERMINE
At x=6, it is beyond its radius of convergence but has not attain its divergence point. thus it is not possible to determine.
Answer: y = 2x + 1
Step-by-step explanation:
use the equation y=mx+b where m is the slope and b is the y-intercept
y-intercept is 1
slope is 2, rise 2 run 1
I'm assuming you're subtracting. It would be 3.9. The second one would be 0.65.