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harkovskaia [24]
3 years ago
5

If alpha and beta are the zeroes of quadratic polynomial ax^2+bx+c , then find alpha^4+beta^4

Mathematics
1 answer:
weqwewe [10]3 years ago
5 0
Ill write A for alpha and B for beta.

AB = c/a  and A + B = -b/a

A^4 + B^4 = (A^2 + B^2)^2  -   2A^2B^2

                 = [(A + B)^2 - 2AB] ^2 - 2A^2B^2

Plugging in the values for A+B and AB we get

A^4 + B^4 = [(-b/a)^2 - 2c/a]^2 - 2(c/a)^2

   =    (b^2 / a^2 - 2c / a)^2 - 2c^2/a^2

  = (b^2 - 2ac)^2  - 2c^2
     ----------------      -----
          a^4                a^2

 =   (b^2 - 2ac)^2 - 2a^2c^2
       -----------------------------
                   a^4
            
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<u>Answer:</u>

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<u>Step-by-step explanation:</u>

We are given the following expression and we are to solve it for the variable x:

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We will find the least common multiple of 2. 6 and 9:

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Simplifying it to get:

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