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SashulF [63]
2 years ago
11

Evaluate.

Mathematics
1 answer:
guajiro [1.7K]2 years ago
4 0

Answer:

24

Step-by-step explanation:

23+4⋅2−7

PEMDAS

Multiply first

23+8−7

Add and subtract from left to right

31-7

24

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11111nata11111 [884]

The picture is blurry and I can't read this

6 0
3 years ago
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Find the measure of angle T
sukhopar [10]

Answer:

100 degrees

Step-by-step explanation:

The measure of angle T is 100 degrees.

5 0
2 years ago
Circle A has center (0, 0) and radius 3. Circle B has center (-5, 0) and radius 1. What sequence of transformations could be use
Dmitrij [34]

A translation of T(x, y) = (- 5, 2) and a dilation with center (- 5, 2) with a scale factor of 1 / 3 are necessary to transform circle A into circle B. (Correct choice: D)

<h3>What sequence of rigid transformations can be done on a circle</h3>

In this problem we must determine the sequence of transformations require to transform circle A into circle B. From analytical geometry we know that the equation of the circle in standard form is:

(x - h)² + (y - k)² = r²

Where:

  • (h, k) - Coordinates of the center.
  • r - Radius of the circle.

Then, we need to apply the following rigid transformations:

Translation

f(x, y) → f(x - h, y - k), where (h, k) is the translation vector.

Dilation with center at the center of the circle

r → k · r, where k is the scale factor.

The circle A is represented by x² + y² = 3, then we derive the expression for the circle B:

f(x, y) → f(x + 5, y - 2)

(x + 5)² + (y - 2)² = 9

r → k · r

(x + 5)² + (y - 2)² = (1 / 3)² · 9

(x + 5)² + (y - 2)² = 1

Then, a translation of T(x, y) = (- 5, 2) and a dilation with center (- 5, 2) are necessary to transform circle A into circle B.

To learn more on rigid transformations: brainly.com/question/28004150

#SPJ1

8 0
1 year ago
Priya's cat weighs 5 1/2 pounds and her dog weighs 8 1/4 pounds.
Lilit [14]

Answer: The cat is 2/3 times as heavy as the dog.


Step-by-step explanation:

The weight of Priya's cat =5\frac{1}{2}\ pounds

Now, 5\frac{1}{2}=\frac{11}{2}\ pounds

The weight of her dog =8\frac{1}{4}\ pounds

8\frac{1}{4}=\frac{33}{4}\ pounds

Let cat is n times heavy as dog.

Then n=\text{cat's weight}\div\text{dog's weight}

n=\frac{{11}{2}\div\frac{33}{4}\\\Rightarrow\ n=\frac{11}{2}\times\frac{4}{33}\\\Rightarrow\ n=\frac{2}{3}

Hence, The cat is 2/3 times as heavy as the dog.

5 0
3 years ago
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Can you tell me if this is proportional and what is the answer plzzz help!!!!
nevsk [136]

10 is proportional, while 11 is not. The answer for 10 is 1.5.

8 0
2 years ago
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