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3 years ago

What is the equation of the graphed line

Mathematics

2 answers:

11Alexandr11 [23.1K]3 years ago

6 0

Answer:

y = 2x + 3

Step-by-step explanation:

The y-intercept is clearly marked: it's b = 3 (or 0, 3).

Going from the point (-3, -3) to the point (0, 3),

x increases by 3 and y increases by 6. Thus, the slope of the line through these two points is m = rise / run = 6 / 3, or m = 2.

Starting with the slope-intercept form of the equation of a straight line:

y = mx + b, we substitute 2 for m and 3 for b, obtaining:

y = 2x + 3

Anon25 [30]3 years ago

6 0

Answer:

y = 2x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 3, - 3) and (x₂, y₂ ) = (0, 3) ← 2 points on the line

m = $\frac{3+3}{0+3}$ = $\frac{6}{3}$ = 2

note the line crosses the y- axis at (0, 3) ⇒ c = 3

y = 2x + 3 ← equation of line

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Crank

Answer:

Confidence interval: (30.1,36.9)

Step-by-step explanation:

We are given the following data set:

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Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1339.9}{40} = 33.5$

$S.D = 11$ (given)

n = 40

Confidence interval:

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$33.5 \pm 1.96(\frac{11}{\sqrt{40}} ) = 6.34 \pm 3.4 = (30.1,36.9)$

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What is the value of 3.5 (11) + 1.9 (11) + 1.6 (11)?

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What is the equation of the graphed line​

What is the equation of the graphed line