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vazorg [7]
3 years ago
5

Two lines are parallel. The equation for the first line is y=-3x+5. Which of the following can't be the equation of the second l

ine?
A. y=-3x+2
B. x-3y=-3
C. 3x+y=-6
D. 6x+2y=2 Two lines are parallel. The equation for the first line is y=-3x+5. Which of the following can't be the equation of the second line?
A. y=-3x+2
B. x-3y=-3
C. 3x+y=-6
D. 6x+2y=2 @Mathematics
Mathematics
1 answer:
Vesnalui [34]3 years ago
4 0
Parallel lines can be distinguished by looking at the value of their slopes. These equations should have the same value of the slope. We are given the equation,

<span>y=-3x+5

From the choices, we see that A, C and D have the same slope with the equation. Therefore, the correct answer is B, it is the equation that can't be parallel with the given equation.</span>
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Answer:

325

Step-by-step explanation:

Notice you are adding 7 everytime.

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a(n) = 10 + 7n

n=0 gives a(0)=10, which is the first term.

so the 46th term has n=45.

a(45)=10 + 7*45=325

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3 years ago
Clayton needs to reflect the triangle below across the line y = x. On a coordinate plane, triangle A B C has points (5.5, 7), (6
Ksju [112]

Answer:

Clayton could use the relationship (x,y) - (y,x) to find the points of the image.

C’ will remain in the same location as C because it is on the line of reflection.

The image and the pre-image will be congruent triangles.

The image and pre-image will not have the same orientation because reflections flip figures

Step-by-step explanation:

Clayton needs to reflect the triangle below across the line y=x

Which statements about the reflection are true? Check all that apply.

Clayton could use the relationship (x,y) - (y,x) to find the points of the image.Clayton could negate both the x and y values in the points to find the points of the image.C’ will remain in the same location as C because it is on the line of reflection.C’ will move because all points move in a reflection.The image and the pre-image will be congruent triangles.The image and pre-image will not have the same orientation because reflections flip figures.

Solution:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.

Reflection is the flipping of a figure over a line. If a point A(x, y) is reflected over the line y=x, the new location is A'(y, x).

If the triangle ABC with vertices A(5.5, 7), B(6, 2), C(4, 4) is reflected over the line y=x, the new location would be A'(7, 5.5), B'(2, 6) and C'(4, 4).

A. Clayton could use the relationship (x,y) - (y,x) to find the points of the image. Reflection across the line y = x is the swapping of the x and y coordinates. Option A is correct

B. Clayton could negate both the x and y values in the points to find the points of the image. Option B is wrong

C. C’ will remain in the same location as C because it is on the line of reflection. C is on the line of reflection, hence it remains the same. Option C is correct.

D. C’ will move because all points move in a reflection.

Option D is wrong.

E. The image and the pre-image will be congruent triangles.

Option E is correct. Reflection preserves the shape and length of an object.

F. The image and pre-image will not have the same orientation because reflections flip figures. Option F is correct

8 0
3 years ago
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