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SpyIntel [72]
3 years ago
6

Calculate the length of the unknown side of this right angled triangle

Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer:

≈ 12.05

Step-by-step explanation:

Pythagora

x = √(9² + 8²)

= √(81 + 64)

= √145

≈ 12.05

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The most popular items at a bakery are its raspberry scones and its lemon poppy
Leno4ka [110]

The system r+l = 46 and 15r + 9l = 396 can be used to determine the number of raspberries boxes and lemon seed boxes sold.

Step-by-step explanation:

Given,

Cost per box of raspberry = $15

Cost per box of lemon seeds = $9

Total boxes sold = 46

Total revenue generated = $396

Let,

r represent the number of raspberries sold

l represent the number of lemon seeds sold

According to given statement;

r+l = 46    Eqn 1

15r + 9l = 396    Eqn 2

The system r+l = 46 and 15r + 9l = 396 can be used to determine the number of raspberries boxes and lemon seed boxes sold.

7 0
3 years ago
Quotient of 794.1 divided by 7.61
AlekseyPX
104.349540079 
 
7.61 x 104.349540079 = 794.1

7 0
3 years ago
Three years back , a father was 24 years older than his son .at present,the father is five times as old as the son.how old will
azamat

Answer:

The son is 5 I think

Step-by-step explanation:

24+3=27

27 divided by 5 = 5.4

round 5.4 to 5 since it is under .5

and you get 5

3 0
3 years ago
PLEASE ANSWERR THISSSS
katrin [286]

Answer:

Should be in the picture linked.

Step-by-step explanation:

If the chart is labeled by five, ten, fifteen, and twenty at the bottom X axis for gallons, then this should be correct. If not, could you take another picture of the problem? I could redo it then. Hopefully I helped, good luck

4 0
2 years ago
Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
3 years ago
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