Answer:
720 miles.
Step-by-step explanation:
Going 60 miles per hour for 12 hours would amount to driving 720 miles in total.
Answer:
what function
Step-by-step explanation:
<h3>
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➷ When you add fractions, you have to have the same denominator whereas, when you multiply them, you don't have to. (In this case the denominators are already the same.) Also, multiplying the fractions would make the result smaller whereas adding them would make it larger.
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Answer:
1) 
2) 
3) 
4) 
Step-by-step explanation:
1) 
Solving using exponent rule: 

So, 
2) 
Using the exponent rule: 
We have:

We also know that: 
Using this rule:

So, 
3) 
Solving:

So, 
4) 
We know that: 

So, 