Question

200 at 6% twice a year how much will Rachel have in ten years

Answer 1

A=P(1+R)^n
A=amount in 10 years
P=original amount (200)
R=rate(o.o6)
n=number of times compunded(20)
A=200x1.06^20
  =641.4270944
Therefore Rachel will have 641.42 in 10 years