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3 years ago

Which properly illustrated in the statement (-2)(+5) = (+5)(-2)?

Mathematics

1 answer:

Maurinko [17]3 years ago

5 0

Answer: 7

Step-by-step explanation:

it is trust me.

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May someone please help this is due a 9:59pm. I have connected a pic.

Tatiana [17]

Answer:Your poopoo

Step-by-step explanation:

4 0

3 years ago

The highest elevation in a small country occurs on a mountain 1,232 meter above sea level, while the lowest elevation in the sam

Arte-miy333 [17]

Answer: 1,259 meters.

Step-by-step explanation:

GIven: The highest elevation in a small country occurs on a mountain above sea level = 1,232 meter

The lowest elevation in the same country occurs below sea level = -27 meters

The difference in elevation between the highest and lowest points = Highest - lowest

= 1232 - (-27) meters

= 1232+27 meters [ (-)(-)=(+) ]

= 1259 meters

Hence, the difference in elevation between the highest and lowest points = 1,259 meters.

6 0

3 years ago

Solving absolute value equation <br> |17(5)|+|3(8)-5|

Alex787 [66]

Answer:

104

Step-by-step explanation:

5 0

3 years ago

Reflect the x axis A B C D

Ronch [10]

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y ) , then

A (- 1, - 17 ) → A' (- 1, 17 )

B (0, - 12 ) → B' (0, 12 )

C (- 5, - 11 ) → C' (- 5, 11 )

D (- 6, - 16 ) → D' (- 6, 16 )

3 0

3 years ago

Verify a(b-c)=ab-ac for a=1.6;b=1/-2;& c=-5/-7

harina [27]

Given:

$a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}$

To verify:

$a(b-c)=ab-ac$ for the given values.

Solution:

We have,

$a=1.6,b=\dfrac{1}{-2},c=\dfrac{-5}{-7}$

We need to verify $a(b-c)=ab-ac$ .

Taking left hand side, we get

$a(b-c)=1.6\left(\dfrac{1}{-2}-\dfrac{-5}{-7}\right)$

$a(b-c)=1.6\left(-\dfrac{1}{2}-\dfrac{5}{7}\right)$

Taking LCM, we get

$a(b-c)=1.6\left(\dfrac{-7-10}{14}\right)$

$a(b-c)=\dfrac{16}{10}\left(\dfrac{-17}{14}\right)$

$a(b-c)=\dfrac{8}{5}\left(\dfrac{-17}{14}\right)$

$a(b-c)=-\dfrac{68}{35}\right)$

Taking right hand side, we get

$ab-ac=1.6\times \dfrac{1}{-2}-1.6\times \dfrac{-5}{-7}$

$ab-ac=-\dfrac{16}{20}-\dfrac{8}{7}$

$ab-ac=-\dfrac{4}{5}-\dfrac{8}{7}$

Taking LCM, we get

$ab-ac=\dfrac{-28-40}{35}$

$ab-ac=\dfrac{-68}{35}$

Now,

$LHS=RHS$

Hence proved.

7 0

3 years ago