3x + 3 = 3y < -- make this 3x - 3y = -3
2x - 6y = 2
multiply by 2 on the first equation
6x - 6y = -6
2x - 6y = 2
subtract them
4x = -8
x = -2
substitute x = -2 into any of the equation
2x - 6y = 2
2(-2) - 6y = 2
-4 - 6y = 2
-6y = 6
y = -1
So the answer is
(-2 , -1)
Answer:
1.) A=Bh-Bh=First Image
2.)A=Bh- πr^2=3rd Image
3.)A=BH + BH/2= Bottom image
4.)A=bh+ bh/2 + πr^2/2= 2nd image
Step-by-step explanation:
Hope this helps! :)
Answer:
The solution is possible
Step-by-step explanation:
Given

Required
Is an output of 200, possible?
To know if it is possible or not, we start by substituting 200 for f(x)

Divide both sides by 5




Take logarithm of both sides

Apply law of logarithm

Divide both sides by log2



for f(x) = 200, x is approximately 5.32
Hence, the solution is possible