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stich3 [128]
4 years ago
10

Help!!!!

Mathematics
1 answer:
Anna35 [415]4 years ago
8 0
7 \frac{2}{15 } + 5 \frac{2}{3} + 9 \frac{3}{15}

Convert mixed number to improper fraction.

\frac{107}{15} + \frac{17}{3} + \frac{148}{15}

Then change all the denominators into a same number

\frac{107}{15} +  \frac{85}{15} +  \frac{148}{15}

Add all the numerators but let all the denominators be same.

\frac{107+85+148}{15} = \frac{340}{15}

Change the improper fraction back into a mixed number..

22  \frac{10}{15} I see that we can still simplify the fraction.. 

22 \frac{10}{15} = 22 \frac{2}{3}

Your final answer is C. 22 \frac{2}{3}
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Dafna1 [17]

Answer:

i(t)=(2/3)(1-e^{-300t})

Step-by-step explanation:

Before we even begin it would be very helpful to draw out a simple layout of the circuit. Then we go ahead and apply kirchoffs second law(sum of voltages around a loop must be zero) on the circuit and we obtain the following differential equation,

-V +Ldi/dt+Ri=0

where V is the electromotive force applied to the LR series circuit, Ldi/dt is the voltage drop across the inductor and Ri is the voltage drop across the resistor. we can re write the equation as,

di/dt+Ri/L=V/L

Then we first solve for the homogeneous part given by,

di/dt+Ri/L=0

we obtain,

i(t)_{h} =I_{max}e^{-Rt/L}

This is only the solution to the homogeneous part, The final solution would be given by,

i(t)=i(t)_{h} +c

where c is some constant, we added this because the right side of the primary differential equation has a constant term given by V/R. We put this in the main differential equation and obtain the value of c as c=V/R by comparing the constants on both sides.if we put in our initial condition of i(0)=0, we obtain I_{max} =V/R, so the overall equation becomes,

I(t)=(V/R)(1-e^{-Rt/L})

where if we just plug in the values given in the question we obtain the answer given below,

i(t)=(2/3)(1-e^{-300t})

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Step-by-step explanation:

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Step-by-step explanation:

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