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3 years ago

Find the difference (-6d+2)-(7+2d)

Mathematics

2 answers:

Hunter-Best [27]3 years ago

7 0

Answer:

-8d-5

Step-by-step explanation:

Cerrena [4.2K]3 years ago

6 0

Answer:

-8d-5

HOPE THIS HELPS

- Todo ❤️

Step-by-step explanation:

-6d-2d=-8d

2-7=-5

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Solve the Equation (NO LINKS AND ONLY IF YOU KNOW PLS)

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3 years ago

Select all statements that are true about the linear equation. y=−2x 4y=−2x 4 the point (0, 2)(0, 2) lies on the graph of the eq

Wittaler [7]

Y = -2x + 4

The graph of the equation is the set of points that are solutions to the equation.

The equation 2x + y = 4 is represented by the same graph.

For point (1, 2): 2 = -2(1) + 4 = -2 + 4 = 2.
Therefore, the point (1, 2) lies on the the graph of the equation.

For the point (0, 2): 2 ≠ -2(0) + 4 = 0 + 4 = 4.
Therefore, the point (0, 2) DOES NOT lie on the graph of the equation.

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3 years ago

Use calculus to find the absolute maximum and minimum values of the function. (round all answers to three decimal places.) f(x)

Allisa [31]

Part A:

Given the function $f(x)=x+2\cos(x)$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow1-2\sin{x}=0 \\ \\ \Rightarrow2\sin{x}=1 \\ \\ \Rightarrow\sin{x}= \frac{1}{2} \\ \\ \Rightarrow x=\sin^{-1}{\frac{1}{2}}= \frac{\pi}{6}$

Using the second derivative test,

$f''(x)=-2cosx \\ \\ \Rightarrow f''\left( \frac{\pi}{6} \right)=-2\cos{\left( \frac{\pi}{6} \right)}=-1.732$

Since the second derivative gives a negative number, the given function has a maximum point at $x=\frac{\pi}{6}$ .

And the maximum point is given by:

$f\left( \frac{\pi}{6} \right)=\frac{\pi}{6}+2\cos\left( \frac{\pi}{6} \right) \\ \\ =0.5236+2(0.8660)=0.5236+1.732 \\ \\ =\bold{2.256}$

i.e. $\left(\frac{\pi}{6},\ 2.256\right)$

Part B:

Given the function $f(x)=e^{-x}-e^{-2x}$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow-e^{-x}+2e^{-2x}=0 \\ \\ \Rightarrow2e^{-2x}=e^{-x} \\ \\ \Rightarrow2e^{-x}=1 \\ \\ \Rightarrow e^{-x}=\frac{1}{2} \\ \\ \Rightarrow-x=\ln \frac{1}{2}=-0.6931 \\ \\ \Rightarrow x=0.6931$

Using the second derivative test,

$f''(x)=e^{-x}-4e^{-2x} \\ \\ \Rightarrow f''(0.6931)=e^{-0.6931}-4e^{-2(0.6931)} \\ \\ =0.5-4e^{-1.386}=0.5-4(0.25)=0.5-1 \\ \\ =-0.5$

Since the second derivative gives a negative number, the given function has a maximum point at $x=0.6931$ .

And the maximum point is given by:

$f(0.6931)=e^{-0.6931}-e^{-2(0.6931)} \\ \\ =0.5-e^{-1.386}=0.5-0.25=\bold{0.25}$

i.e. (0.693, 0.25)

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3 years ago

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Step-by-step explanation:

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4 years ago

How do you do 2y,-4y by elimination?

AysviL [449]

2y-4y=-2y

That is the answer

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3 years ago

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