Find the median of the data.<br><br> 5, 8, 4, 6, 8

Gwar [14]

Alright

for a 45-45-90 triangle, if the legs are x then the hytponuse is x√2

so LM=x√2 is right
NM=x

also, tan=oposite side/adjacent side
so that would be LN/MN or MN/LN=x/x=1

so that would be tan(45)=1

so you want to check the 1st one, 3rd one and 5th one

NM=x
LM=x√2
tan(45°)=1 are the answers

4 0

3 years ago

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HELPPPPPPPPPPP PLEASEEEEEEE <br> What point does the line pass through?

Lina20 [59]

Answer:

It passes through (1,1).

5 0

3 years ago

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A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed

Natali [406]

Answer:

$t=\frac{1.17-1.04}{\sqrt{\frac{0.11^2}{8}+\frac{0.09^2}{8}}}}=2.587$

$df=n_{1}+n_{2}-2=8+8-2=14$

Since is a one sided test the p value would be:

$p_v =P(t_{(14)}>2.587)=0.0108$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, we have enough evidence to reject the null hypothesis on this case and the 25 mil film have a mean greater than the 20 mil film so then the claim is not appropiate

Step-by-step explanation:

Data given and notation

$\bar X_{1}=1.17$ represent the mean for the sample 1 (25 mil film)

$\bar X_{2}=1.04$ represent the mean for the sample 2 (20 mil film)

$s_{1}=0.11$ represent the sample standard deviation for the sample 1

$s_{2}=0.09$ represent the sample standard deviation for the sample 2

$n_{1}=8$ sample size selected for 1

$n_{2}=8$ sample size selected for 2

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if reducing the film thickness increases the mean speed of the film, the system of hypothesis would be:

Null hypothesis: $\mu_{1} \leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{1.17-1.04}{\sqrt{\frac{0.11^2}{8}+\frac{0.09^2}{8}}}}=2.587$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=8+8-2=14$

Since is a one sided test the p value would be:

$p_v =P(t_{(14)}>2.587)=0.0108$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, we have enough evidence to reject the null hypothesis on this case and the 25 mil film have a mean greater than the 20 mil film so then the claim is not appropiate

4 0

3 years ago

hugo is saving for a new baseball glove. he saves $10 the first week, and $6 each week for the next 6 weeks. the expression 10 +

BigorU [14]

So if Hugo has saved $10 the first week and $6 for the next 6 weeks the answer would be $46.

you can either add up 6 six times or you can multiple 6 by 6.
6+6+6+6+6+6=36 or 6×6=$36

then you add the $10 from the first week & the $36 from the $6 you saved for 6 weeks to get your final answer of $46.
$36+$10=$46

5 0

3 years ago

Solve for x, in terms of y: 2 3 x + 1 5 y = 2

satela [25.4K]

Answer:

(2/3)x - (1/5) y = 10. to solve for x in terms of y: (2/3)x - (1/5) y = 10. (2/3)x = 10 + (1/5)y. x = (10 + (1/5)y)(3/2). x = 15 + 3/10 y. if y = 0; x = 15. to solve for y in terms ...

Step-by-step explanation:

6 0

3 years ago

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Find the median of the data. 5, 8, 4, 6, 8