Its like a polynomial.
cosx=x
so it'll be like
2x^2+3x-2=0
<span>(2x−1)(x+2)
</span>
which makes your life easy because you do not have to solve cos(x)=−2 because it cannot be, so only solve cos(x)=1/2
................................
Answer:
Given the expression: ![3y^3-2y[4y-y(y-3)]-[2y(y+1)-3y(y^2-1)]](https://tex.z-dn.net/?f=3y%5E3-2y%5B4y-y%28y-3%29%5D-%5B2y%28y%2B1%29-3y%28y%5E2-1%29%5D)
The distributive property says that:

Applying distributive property on the given expression, we have;
![3y^3-2y[4y-y^2+3y]-[2y^2+2y-3y^3+3y]](https://tex.z-dn.net/?f=3y%5E3-2y%5B4y-y%5E2%2B3y%5D-%5B2y%5E2%2B2y-3y%5E3%2B3y%5D)
again apply the same property we have
![3y^3-8y^2+2y^3-6y^2-[2y^2+2y-3y^3+3y]](https://tex.z-dn.net/?f=3y%5E3-8y%5E2%2B2y%5E3-6y%5E2-%5B2y%5E2%2B2y-3y%5E3%2B3y%5D)
or

Like terms are those terms which have same variables to the same power.
Combine like terms;

Therefore, the simplified form of the given expression is, 