Find the value of x for which l || m.

Mathematics

1 answer:

omeli [17]3 years ago

3 0

A. 24 I think but I do not know where you x is in the problem.

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Is the following UPC code valid? 375407370090. PLEASE SHOW OR EXPLAIN!!!

MAXImum [283]

Answer:

The UPC is not valid..

Step-by-step explanation:

The Universal Price Code is represented in the form of bars which is scanned when we purchase something.

The last digit of the UPC is the check digit.

Give UPC = 375407370090

To check whether the UPC is valid or not.

Step 1:

Add the digits at odd positions.

3 + 5 + 0 +3 + 0 + 9 = 20

Step 2:

Multiply the number obtained in step 1 by 3

20*3 = 60

Step 3:

The digits at even positions have to be added. The last digit has to be ignored as it is a check digit.

7 + 4 + 7 +7 +0 = 25

Step 4:

Add the numbers obtained in Step 2 and step 3

60 + 25 = 85

Step 5:

The number obtained in step 5 is subtracted from the next multiple of 10.

In the above case,

85 will be subtracted from 90.

90 - 85 = 5

For a valid UPC, the answer to step 5 is equal to the last digit of UPC.

In the above case, the answer is 5 which is not equal to zero.

So, the UPC is not Valid.

4 0

3 years ago

If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac

mezya [45]

There are $\binom{52}4$ ways of drawing a 4-card hand, where

$\dbinom nk = \dfrac{n!}{k!(n-k)!}$

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are $\binom{13}4$ ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are $\binom41$ ways of picking a card of any given value. We draw 4 cards from the deck, so there are $\binom41^4$ possible hands in which each card has a different value.