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eduard
4 years ago
14

The components of vector a⃗ are ax = + 3.90 and ay = -4.00. What is the angle measured counterclockwise from the +x-axis to vect

or a⃗ ?
Mathematics
1 answer:
Genrish500 [490]4 years ago
3 0

The angle is the arctangent of the ratio of ay to ax. Since ay is negative and ax is positive, it is a 4th-quadrant angle.

... arctan(ay/ax) = arctan(-4.00/3.90) ≈ 314.27°

... about 5.48513 radians

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Find the solution of the inequality -3n < 81
posledela

Answer:

n<-27

Step-by-step explanation:

you have to get n by itself, to do this divide -3 from both sides of the equations.

-3n/-3<81/-3

n<-27

the answer is n<-27

8 0
3 years ago
Find the solution to the equation below.<br> 2x^2+3x-20=0
mariarad [96]

Answer:

  x = -4, 5/2

Step-by-step explanation:

A quadratic can be solved may ways, including graphing, factoring, and the quadratic formula. You can also check possible answers by making use of the relationships between solutions and the coefficients.

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A graph is attached. It shows the solutions to be -4 and 5/2.

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When factored, the equation becomes ...

  (2x -5)(x +4) = 0 . . . . . has solutions x=-4, x=5/2 (these make the factors zero)

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Using the quadratic formula, the solutions of ax^2 +bx +c = 0 are found from ...

  x = (-b±√(b²-4ac))/(2a)

  x = (-3±√(3²-4(2)(-20))/(2(2)) = (-3±√169)/4 = {-16, +10}/4

  x = {-4, 5/2}

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For ax^2 +bx +c = 0, the solutions must satisfy ...

  product of solutions is c/a = -20/2 = -10

Only the first and last choices have this product.

  sum of solutions is -b/a = -3/2

Only the first choice (-4, 5/2) has this sum.

8 0
3 years ago
Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval. Limit Interval lim
geniusboy [140]

Answer:

The corresponding definite integral may be written as

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x

The answer of the above definite integral is

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98

Step-by-step explanation:

The given limit interval is

\lim_{||\Delta|| \to 0}  \sum\limits_{i=1}^n (4c_i + 11) \Delta x_i

[a, b] =  [-8, 6]

The corresponding definite integral may be written as

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x

\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x

Bonus:

The definite integral may be solved as

\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x \\\\\frac{4x^2}{2} + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\2x^2 + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\ 2(6^2 -(-8)^2 ) + 11(6 - (-8) \\\\2(36 - 64 ) + 11(6 + 8) \\\\2(-28 ) + 11(14) \\\\-56 +154 \\\\98

Therefore, the answer to the integral is

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x  = 98

5 0
3 years ago
Please help with number 16
Andre45 [30]

Answer:

2) reflexive property

3) given

4) substitution postulate

5) substitution postulate

6) addition postulate

7) partition postulate

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Step-by-step explanation:

7 0
3 years ago
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Rina8888 [55]

Answer: He will have 88 cups of punch left over

Step-by-step explanation:

6 0
3 years ago
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