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2 years ago

10

An inverted conical water tank with a height of 12 ft and a radius of 3 ft is drained through a hole in the vertex. If the water

level drops at a rate of 1 ft/min, at what rate is water (in ft3/min) draining from the tank when the water depth is 8 ft

1 answer:

Irina-Kira [14]2 years ago

3 0

Answer:

dhdt≃0.283ft3s

Step-by-step explanation:

dhdt≃0.283ft3s

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M is the centroid (center of gravity) of △ABC, line k goes thru M and intersects AB and AC . The distances of the vertices B and

lana [24]

Answer:

30

Step-by-step explanation:

The midpoint of BC will be a distance from line k that is the average of the distances of B and C: (17+13)/2 = 15. Call that midpoint P. We know distance MP is half of distance MA. This same relationship will hold with respect to the distances from P and A to any line through M. That is, the distance from line k (through M) is twice the distance from P to line k: 30 units.

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3 years ago

51^7 -51^6 by 25<br> __*25

BartSMP [9]

Answer:

Step-by-step:

51⁷-51⁶ = 51⁶(51-1) = 51⁶(50)

50 is divisible by 25, so 51⁷-51⁶ is divisible by 25.

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2 years ago

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The double number line shows how many bananas are needed to make 111 loaf of banana bread.

skelet666 [1.2K]

Answer:

Chart

Number of loaves Number of Bananas

1 2 1/2

2 5

4 10

Step-by-step explanation:

My friend helped me with this and since I saw no answer here I wanted to help YOU!!!!

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3 years ago

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

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2 years ago

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Llana [10]

Answer:

y = 9/2x -6.5

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2 years ago