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love history [14]
3 years ago
7

PLEASE HELP 15 points

Mathematics
2 answers:
pshichka [43]3 years ago
7 0

Answer:

B, y+6=-4(x-2)

Step-by-step explanation:

since you need a perpendicular line, the slope has to be the opposite reciprocal. 4/1 or 4 is the reciprocal of 1/4, and to make it the opposite reciprocal, you need to change it to negative. for the coordinates (-2,-6), you need to use it in the equation y-y1=m(x-x1)

laila [671]3 years ago
4 0
I think it’s B because I did some calculations and got that I hope I’m right just see first
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I really need help someone pls help
ArbitrLikvidat [17]
5/6 is always going to my equal to itself. o divide the two and see what you get
8 0
3 years ago
Read 2 more answers
What is slope of the line parallel to the line containing points (2,5) and (6,-11)
Ksivusya [100]

The parallel lines have the same slope.

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (2, 5) and (6, -11).

Substitute:

m=\dfrac{-11-5}{6-2}=\dfrac{-16}{4}=-4

6 0
4 years ago
Hello me with A and B please. And explain how to do it if you can.
prisoha [69]
A)   The larger and small triangles are similar, so

8/10 =  x/15
x =  (8*15)/10 =  12 

b)find the altitude x
tan 40 = x / 5
x = 5 tan 40 = 4.195


By Pythagoras theorem:-

y =  sqrt ( 4.195^2 + 11^2)

y =  11.8  to 3 significant figures
8 0
4 years ago
What is the value of x
attashe74 [19]
The value of X in this question is 46                 
4 0
3 years ago
Read 2 more answers
Find all of the critical points of p (t). p (t) = t 2 + 5t + 6.
svp [43]

Please, use " ^ " to denote exponentiation: p(t) = t^2 + 5t + 6.

To find the critical points, differentiate p(t) with respect to t, set the result = to 0, and then solve the resulting equation for t:

p '(t) = 2t + 5 = 0

Solving for t: 2t = -5, and so t = -5/2. (-5/2, p(-5/2)) is the critical point. That evaluates to (-5/2, -0.25). This happens to be the vertex of a parabola that opens up.

8 0
4 years ago
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