Question

The sum of the squares of three consecutive numbers is 194. What are these squares?

Answer 1

The 3 consecutive integers are

n
n + 1
n + 2

Then

n2 + (n + 1)2 + (n + 2)2 = 194

n2 + (n2 + 2n + 1) + (n2 + 4n + 4) = 194

3n2 + 6n + 5 = 194

3n2 + 6n - 189 = 0

n2 + 2n - 63 = 0

(n - 7)(n + 9) = 0

n = 7 or -9

If n = 7, the 3 integers are 7, 8, and 9
If n = -9, the 3 integers are -9, -8, and -7




Mark brainliest please



Hope this helps you