THis equals the number of permutations of 4 from 6.
= 6P4 = 6! / (6 - 4)! = 6! / 2! = 720/2 = 360 answer
1.) Beachy-Keen
2.) shorething
3.) shorething
4.) Beachy-Keen
5.) shorething
let me know if you think any of these are incorrect hope it helps
First you make the mixed numbers/fractions into improper fractions. After that, you must find the common denominator, the LCM of 9 and 6 (for the 2nd problem). After that, if you can, simplify the fraction to lowest terms, which also includes making it a mixed number/fraction.
I hope this helps! :)
Answer:
2630 g
Step-by-step explanation:
From the given information:
Given that:
mean (μ) = 3750 g
Standard deviation (σ) = 500
Suppose the hospital officials demand special treatment with a percentage of lightest 3% (0.03) for newborn babies;
Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;
P(Z < z₁) = 0.03
Using the Excel Formula; =NORMSINV(0.03) = -1.88
z₁ = - 1.88
Using the test statistics z₁ formula:


By cross multiply, we have:
-1.88 × 500 = X - 3570
-940 = X - 3570
-X = -3570 + 940
-X = -2630
X = 2630 g
Hence, 2630 g is the required weight of birth that differentiates the babies that needed special treatment from those that do not