Flowering plants reproduce sexually through a process called pollination. The flowers contain male sex organs called stamens and female sex organs called pistils. The anther is the part of the stamen that contains pollen. This pollen needs to be moved to a part of the pistil called the stigma .
Answer:
The correct answer is they show weak positive gram staining reaction.
Explanation:
<em>Mycobacterium phlei </em>is a rod-shaped species of the genus Mycobacterium. They are acid-fast bacteria with mycolic acids rich cell wall due to which gram stain cannot penetrate easily and show light purple color while staining.
When gram staining is performed on the <em>M.phlei </em>, they take light purple color which indicates that it is a gram-positive bacteria and is related to Actinobacteria phylum of the gram-positive bacteria.
Thus, <em>M. phlei</em> is a gram-positive bacteria.
Answer:
(a) 1/2; (b) no
Explanation:
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.
In contrast to this, her husband is diseased so his genotype will be XᵇY.
The Punnett square diagram related to the cross is attached.
(a) Proportion of their sons expected to be G6PD is 1/2:
They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.
(b) If the husband were G6PD deficient, the answer will not change.
The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.