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Answer:
eleven more than a number squared, decreased
by six;
evaluate when t = 5
Evaluating Expressions
Write the expression as 11 +t2 -6
Write the expression as 11 +2t -6
Write the expression as t underscore 2
The value when t = 5 is 16.
The value when t = 5 is 30.
The value when t = 5 is 7.5.
Answer:
the ratio is 12:16=3/4
So AE:5+AE=3/4
4AE=15+3AE
AE=15
Step-by-step explanation:
Answer:
The probability that a jar contains more than 466 g is 0.119.
Step-by-step explanation:
We are given that a jar of peanut butter contains a mean of 454 g with a standard deviation of 10.2 g.
Let X = <u><em>Amount of peanut butter in a jar</em></u>
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean = 454 g
= standard deviation = 10.2 g
So, X ~ Normal(
)
Now, the probability that a jar contains more than 466 g is given by = P(X > 466 g)
P(X > 466 g) = P(
>
) = P(Z > 1.18) = 1 - P(Z
1.18)
= 1 - 0.881 = <u>0.119</u>
The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.
Answer:
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
Step-by-step explanation:
We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.
Firstly, Let X = women's gestation period
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= average gestation period = 270 days
= standard deviation = 9 days
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X
261)
P(X < 279) = P(
<
) = P(Z < 1) = 0.84134
P(X
261) = P(
) = P(Z
-1) = 1 - P(Z < 1)
= 1 - 0.84134 = 0.15866
<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>
Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.