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Gennadij [26K]
2 years ago
8

Write the inequality |x - 2| < 3 without absolute value symbols.

Mathematics
1 answer:
kotegsom [21]2 years ago
4 0

|x-2| < 3\Rightarrow x-2 < 3\ \wedge\ x-2 > -3\ \ \ \ |+2\\\\x < 5\ \wedge\ x > -1

x\in(-1,\ 5)

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Solve the system by graphing.
igor_vitrenko [27]

Answer:

Hi There the correct answer is {x,y} = {-1,-10}  

 

System of Linear Equations entered :

  [1]    3x - y = 7

  [2]    4x - 2y = 16

Graphic Representation of the Equations :

   y + 3x = 7        -2y + 4x = 16  

 

 

Solve by Substitution :

// Solve equation [1] for the variable  y  

 

 [1]    y = 3x - 7

// Plug this in for variable  y  in equation [2]

  [2]    4x - 2•(3x-7) = 16

  [2]    -2x = 2

// Solve equation [2] for the variable  x  

  [2]    2x = - 2  

  [2]    x = - 1  

// By now we know this much :

   x = -1

   y = 3x-7

// Use the  x  value to solve for  y  

   y = 3(-1)-7 = -10  

Solution :

{x,y} = {-1,-10}  

Hope it helps!

8 0
2 years ago
Please help me !!!!!
romanna [79]

Answer:

3/8

Step-by-step explanation:

If 1 and 3 are odd numbers then all you have to do is count the number of 1 and 3's(3). then count the number of numbers (8).

3 0
2 years ago
What is the answer to this math question
Vilka [71]

(19 {b}^{3}  + 16 {f}^{3} ) \times 2 {b}^{5}  = 38 {b}^{8}  + 32 {b}^{5}  {f}^{3}
8 0
2 years ago
What is the LCM of 8 and 10
iragen [17]
40


8x5=40
10x4=40

Hope this helps
3 0
2 years ago
Two urns each contain green balls and blue balls. Urn I contains 4 green balls and 6 blue balls, and Urn II contains 6 green bal
Morgarella [4.7K]
Urn 1 = 4 green balls and 6 blue balls, a total of 10 balls
Urn 2 = 6 green balls and 2 blue balls, a total of 8 balls.

Probability of blue balls:
Urn 1 : P = 6/10 
Urn 2 : P = 2/8 

Probability that both balls are blue:
6/10 * 2/8 = 6*2 / 10*8 = 12/80 = 6/40 = 3/20 

Answer is B. 3/20
3 0
3 years ago
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