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Delvig [45]
3 years ago
14

How many permutations are possible for 11 objects taken 7 at a time?

Mathematics
2 answers:
Lemur [1.5K]3 years ago
9 0
11P7   =   11!           11*10*9*8*7*6*5*4*3*2*1
              --------  =   ------------------------------------  =    1,663,200
              (11-7)!                   4*3*2*1
scZoUnD [109]3 years ago
5 0
There are 330 combinations and 1,663,200 individual permutations.
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Answer:

a) The interval for those who want to go out earlier is between 43.008 and 46.592

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Step-by-step explanation:

Given that:

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Margin of error (e) = ±4% =

a) The probability of those who wanted to get out earlier (p) = 35% = 0.35

The mean of the distribution (μ) = np = 128 * 0.35 = 44.8

The margin of error = ± 4% of 448 = 0.04 × 44.8 =  ± 1.792

The interval = μ ± e = 44.8 ± 1.792 = (43.008, 46.592)

b) The probability of those who wanted to start school get out later (p) = 39% = 0.39

The mean of the distribution (μ) = np = 128 * 0.39 = 49.92

The margin of error = ± 4% of 448 = 0.04 × 49.92 =  ± 1.9968

The interval = μ ± e = 44.8 ± 1.792 = (47.9232, 51.9168)

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Step-by-step explanation:

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