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Softa [21]
2 years ago
10

Someone help, this is kinda boring...

Mathematics
1 answer:
givi [52]2 years ago
8 0

Answer:

Step-by-step explanation:

a+b =1\dfrac{3}{5} + (-2)\\\\=\dfrac{8}{5}-\dfrac{2*5}{1*5}\\\\=\dfrac{8-10}{5}\\\\\\=\dfrac{-2}{5}\\\\\\2-c = 2-[-7] = 2+7 = 9\\\\\\dfrac{- I a + b I}{2-c}=\dfrac{\dfrac{-2}{5}}{9}\\\\=\dfrac{-2}{5}*\dfrac{1}{9}\\\\=\dfrac{-2}{45}\\\\

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3 years ago
Which function is the inverse of f(x) = –5x – 4?
makvit [3.9K]
Y = -5x - 4
switch x and y and solve for y
x = -5y - 4
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4 0
4 years ago
Consider the differential equationy′′+3y′−10y=0.(a) Find the general solution to this differential equation.(b) Now solve the in
RSB [31]

Answer:

Y= 2e^(5t)

Step-by-step explanation:

Taking Laplace of the given differential equation:

s^2+3s-10=0

s^2+5s-2s-10=0

s(s+5)-2(s+5) =0

(s-2) (s+5) =0

s=2, s=-5

Hence, the general solution will be:

Y=Ae^(-2t)+ Be^(5t)………………………………(D)

Put t = 0 in equation (D)

Y (0) =A+B

2 =A+B……………………………………… (i)

Now take derivative of (D) with respect to "t", we get:

Y=-2Ae^(-2t)+5Be^(5t)   ....................... (E)

Put t = 0 in equation (E) we get:

Y’ (0) = -2A+5B

10  = -2A+5B ……………………………………(ii)

2(i) + (ii) =>

2A+2B=4 .....................(iii)

-2A+5B=10 .................(iv)

Solving (iii) and (iv)

7B=14

B=2

Now put B=2 in (i)

A=2-2

A=0

By putting the values of A and B in equation (D)

Y= 2e^(5t)

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First, we subtract 12x from both sides. We then get -4y=-12x+48. We then divide this by -4 on both sides to get the y by itself. We then get that the equation is y=3x-12. 
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