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navik [9.2K]
3 years ago
15

at the cafe, Rebecca can choose to earn $10 per hour plus a $60 starting bonus or earn $12 per hour with no starting bonus. afte

r how many hours of work will she earn the same amount of both payment options? write an equation to solve the problem. solve.
Mathematics
1 answer:
qwelly [4]3 years ago
8 0
Hi there! The answer is 30 hours.

Let the number of worked hours be represented by X.

The total earn of option 1, would then be 10X + 60
The total earn of option 2, would then be 12X

We end up with the following equation:
10x + 60 = 12x
Subtract 10X from both sides.

60 = 2x
Divide both sides by 2.

x = 30
Therefore, after 30 hours of work Rebecca will earn the same amount of money.
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Crystal earns $5.50 per hours mowing lawns. Write a rule to describe how the amout of money m earned is a function of the number
ra1l [238]
She earns $5.50 for every hour so:
m = 5.5h
3 hours and 45 minutes is 3.75 hours.
m = 5.5(3.75)
m = 20.625
After rounding, she earns $20.63.
4 0
4 years ago
Find the value of x.<br> х= 2<br> х= 3<br> х= 33<br> х= 52
nlexa [21]

Answer:

x = 3

Step-by-step explanation:

The external angle of a triangle is equal to the sum of the 2 opposite interior angles

∠ QRT is an external angle, thus

∠ QRT = ∠ RTS + ∠ RST, substitute values

45x = 25x + 57 + x

45x = 26x + 57 ( subtract 26x from both sides )

19x = 57 ( divide both sides by 19 )

x = 3

6 0
3 years ago
If f(x) - 4x2-3 and g(x) = x+1, find (f - g)(x).
Harrizon [31]

Answer:

4x^2-x-4

Step-by-step explanation:

f(x) = 4x^2-3 and g(x) = x+1,

(f - g)(x)= 4x^2-3 -( x+1)

Distribute the minus sign

            =4x^2-3 - x-1

Combine like terms

            =4x^2-x-4

6 0
3 years ago
Read 2 more answers
In an effort to estimate the mean amount spent per customer for dinner at a major Atlanta restaurant, data were collected for a
Softa [21]

Answer:

95% Confidence interval = (23.4,26.2)

Step-by-step explanation:

In this problem we have to develop a 95% CI for the mean.

The sample size is n=49, the mean of the sample is M=24.8 and the standard deviation of the population is σ=5.

We know that for a 95% CI, the z-value is 1.96.

The CI is

M-z*\sigma/\sqrt{n}\leq\mu\leq M+z*\sigma/\sqrt{n}\\\\24.8-1.96*5/\sqrt{49}\leq\mu\leq 24.8+1.96*5/\sqrt{49}\\\\ 24.8-1.4\leq\mu\leq 24.8+1.4\\\\23.4\leq\mu\leq 26.2

5 0
4 years ago
During the month of June, Ava kept track of the number of days she saw birds in her garden. She saw birds on 18 days of the mont
kirza4 [7]
There are 30 days in the month of June. Out of the 30 days, Ava saw birds on 18.

P(bird)=18/30

We can simplify the fraction by dividing both sides by 2.

P(bird)=18/30=9/15

9/15=0.6=60%

Theres a 9/15 or 60% chance that she will see a bird on July 1st.


3 0
3 years ago
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