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3 years ago

What is 2x2, I keep on getting it wrong. Can u please help, Thank you

Mathematics

2 answers:

Soloha48 [4]3 years ago

8 0

Your answer should be 4!

aleksandr82 [10.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

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What is a regular tessellation? How many regular tessellations are possible? Why aren’t there infinitely many regular tessellati

Minchanka [31]

Answer:

Step-by-step explanation:

What is a regular tessellation?

A regular tessellation is a pattern made by repeating a regular polygon. In simpler words regular tessellations are made up entirely of congruent regular polygons all meeting vertex to vertex.

How many regular tessellation are possible?

There are only 3 regular tessellation.

1. Triangle

2. Square

3. Hexagon

Why aren't there infinitely many regular tessellations?

Not more than 3 regular tessellations are possible because the sums of the interior angles are either greater than or less than 360 degrees....

5 0

4 years ago

What is the next number in this geometric sequence?

Anna11 [10]

Answer:

C. -262.44

Step-by-step explanation:

-3.24, 9.72,-29.16, 87.48

-3.24*-3= 9.72, 9.72*-3= -29.16, -29.16*-3= 87.48

the rule for this sequence is multiplying by -3

87.48*-3= -262.44

8 0

3 years ago

Consider the points P(0,5), Q(9, 2), R(7, -4), and S(-2, -1). What type of quadrilateral

Ghella [55]

Answer:

a trapezium

Step-by-step explanation:

by plotting and joining the points you will see a quadilateral with four sides which has one pair of opposite sides parallel but not equal and that is a trapezium

7 0

3 years ago

What is the solution of -8/2y-8=5/y+4 - 7y+8/y^2-16

blsea [12.9K]

Answer:

Step-by-step explanation:

$Domain:\\\\2y-8\neq0\ \wedge\ y+4\neq0\ \wedge\ y^2-16\neq0\\\\2y\neq8\ \wedge\ y\neq-4\ \wedge\ y^2\neq16\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq\pm\sqrt{16}\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq-4\ \wedge\ y\neq4\\\\\boxed{y\neq-4\ \wedge\ y\neq4}\\\\===========================$

$\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-4^2}\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{(y-4)(y+4)}\qquad\text{multiply both sides by (-2)}\\\\\dfrac{8}{y-4}=-\dfrac{10}{y+4}+\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{add}\ \dfrac{10}{y+4}\ \text{to both sides}\\\\\dfrac{8}{y-4}+\dfrac{10}{y+4}=\dfrac{14y+16}{(y-4)(y+4)}$

$\dfrac{8(y+4)}{(y-4)(y+4)}+\dfrac{10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{8(y+4)+10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{use the distributive property}\\\\\dfrac{8y+32+10y-40}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{combine like terms}\\\\\dfrac{(8y+10y)+(32-40)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{18y-8}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\iff18y-8=14y+16\\\\18y-8=14y+16\qquad\text{subtract 14y from both sides}$

$4y-8=16\qquad\text{add 8 to both sides}\\\\4y=24\qquad\text{divide both sides by 4}\\\\y=8\in D$

8 0

3 years ago

Solve the equation by completing the

Pie

Answer:

Does the unkown num have a pr

Step-by-step explanation:

http/answerme.cm

4 0

2 years ago