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2 years ago

I’m stuck on this question please help x

Mathematics

1 answer:

MrRissso [65]2 years ago

6 0

Answer:

a = -3 and b=5

Step-by-step explanation:

Given that 10 can be written as 2*5 or √2*√2*5, and √18 can be written as √(2*9) or √2*√9 or 3√2, you can write the fraction as:

$\frac{5\cdot\sqrt2\cdot\sqrt2-3\sqrt2}{\sqrt2}$

So getting rid of the √2 factor, you get 5√2 - 3, so a=-3 and b=5

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What is equation of the line that is parallel to the line of the y-1=4(x+3) and passes through the the point (4,3)

tangare [24]

Answer:4x+12

Step-by-step explanation:

4 times x is 4x and 4 times 3 is 12

6 0

3 years ago

Is 8.3 greater than 83 tenths?

kati45 [8]

Answer:

Step-by-step explanation:

They are equal

83 tenths divided by 10 is 8.3

<u>Hope this helps :-)</u>

8 0

4 years ago

Armando’s home insurance has

igomit [66]

Answer:

a. Armando pays 2500

b The insurance pays 16900

Step-by-step explanation:

Armando has to pay 2500 always and the insurance company will pay all thats left to pay is what i understand by the question and the total payment both have to do is 19400.

19400

2500 = 16900

7 0

1 year ago

Which is equivalent to sin^-1(.75)

Neko [114]

<h2>Answer: 0.85 radians</h2>

Step-by-step explanation:

We have the following trigonometric expression:

$sin^{-1}(0.75)=arcsin(0.75)$

The result of this calculation is:

$sin^{-1}(0.75)=48.59\°$ where the angle is in degrees

If $360\°=2\pi rad$ then:

$48.59\°(\frac{2\pi rad}{360\°}=0.848 rad \approx 0.85 rad$

Therefore the answer is 0.85 radians

3 0

3 years ago

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

6 0

4 years ago