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3 years ago

Lumar needed to pay $5 to enter an arcade. She needs to pay $0.30 for each game she plays.

Mathematics

1 answer:

Marrrta [24]3 years ago

6 0

Answer:

x=game played

y=total amount spent

a) 5+0.3x=y

b) (44-5)/0.3=y

39/0.3=y

130=y

c) 30/0.3=100

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A/ab-bsquare + b/ab-asquare?

lord [1]

Answer:

$\dfrac{(a+b)}{ab}$

Step-by-step explanation:

The given expression is :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}$

It can be solved as follows :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}$

So, the solution of the given expression is equal to $\dfrac{(a+b)}{ab}$ .

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3 years ago

Refer to the image, please.

viva [34]

Answer:

Step-by-step explanation:

140*.60, 140*.55

=84 - 77 = 7

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3 years ago

2. Mandla spent one quarter of his pocket money on sweets. a. What fraction does he have left? b. If he had R40 pocket money, ho

kykrilka [37]

Answer:

a. 3/4 of pocket money left

b. R10

Step-by-step explanation:

a. 4/4 - 1/4 = 3/4

b. 40/4 = 10 = 1/4 of pocket money

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.. . . . . . . . . . . . . . ..

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