0.18y + 0.03y + 240 = 1290
0.21y + 240 = 1290
0.21y = 1050
y= 5,000
18 or 3 * 6 because to find out how many possible contengencys you muktiplyy the factors.
Answer:
0.69
Step-by-step explanation:
Hope this helps..
Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
