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3 years ago

Answer is D)-4 but please explain how to get it

Mathematics

2 answers:

Monica [59]3 years ago

7 0

Answer:

Step-by-step explanation:

We could plug x into the equation but to make it easier we simplify it first

$\frac{1}{x} -\frac{1}{x+1}$

$-\frac{1}{x+1} + \frac{1}{x}$

$-\frac{1}{2x+1}$

x = -1/2

-2-2 = -4

Mama L [17]3 years ago

3 0

The answer is d) -4

You do

1/-1/2-1/1/2

-1/1/2-1/1/2

-2-2

-4

. . . . . .

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Please please help please

Readme [11.4K]

Step-by-step explanation:

its .86 which is closer to .87

so choose the first one

7 0

3 years ago

Read 2 more answers

In the rectangle below,

STALIN [3.7K]

Answer:

Step-by-step explanation:

In a rectangle, diagonals are equal and bisect each other

BE = AE

6x - 5 = 2x + 7

6x - 2x - 5 = 7

4x - 5 = 7

4x = 7 + 5

4x = 12

x = 12/4

x = 3

AE = 2x + 7

= 2*3 + 7

= 6 + 7

AE = 13

AC = 13 + 13

AC = 26

m∠EBC = 50

In rectangle, each angle is 90

m∠ABE + m∠EBC = 90

m∠ABE + 50 = 90

m∠ABE = 90 - 50

m∠ABE = 40

In rectangle, AB // DC and DB transversal

m∠ECD = m∠ABE { alternate interior angles}

m∠ECD = 40

8 0

3 years ago

If the sum of three consecutive intergers is 75, what is the greatest of the integers

Ira Lisetskai [31]

Answer:

24,25,26

Step-by-step explanation:

7 0

2 years ago

Triangle P Q R is shown. The length of P Q is 17, the length of Q R is 15, and the length of P R is 14. Law of cosines: a2 = b2

Maksim231197 [3]

Answer:

P = 57°

Step-by-step explanation:

Given the following :

PQ = 17

QR = 15

PR = 14

Using the cosine formula since the length of the three sides are given:

a2 = b2 + c2 – 2bccos(A)

To find P:

QR^2 = PQ^2 + PR^2 – 2(PQ)(PR)cos(P)

15^2 = 17^2 + 14^2 – 2(17)(14)cos(P)

225 = 289 + 196 - 476 cosP

476*CosP = 485 - 225

476*CosP = 260

CosP = 260/476

CosP = 0.5462184

P = Cos^-1(0.5462184)

P = 56.892029

P = 57°

8 0

3 years ago

If a,b,c,d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)(x+d)(x^2+ex+1), what is the value of a+b+c+d+e?

Irina18 [472]

Answer:

Step-by-step explanation:

Hello,

If $X=x^2$ it becomes

$X^3-289X^2-X+289=(X^2-1)(X-289)$

and $289=17^2$

$X^2-1=(X-1)(X+1)=(x^2-1)(x^2+1)=(x+1)(x-1)(x^2+1) \\\\x^2-289=x^2-17^2=(x-17)(x+17)$

So,

$x^6-289x^4-x^2+289=(x^2-1)(x^2+1)(x^2-289)=(x-1)(x+1)(x+17)(x-17)(x^2+1)$

a = 1

b = 1

c = 17

d = 17

e = 0

Then a + b + c + d + e = 36

Thanks

3 0

3 years ago