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dmitriy555 [2]
4 years ago
5

Anyone know how to solve this... ​

Mathematics
2 answers:
solmaris [256]4 years ago
8 0

Answer:

see below

Step-by-step explanation:

D = 1 - ∑(4/125)²

D = 1 - (2/5³)²

D = 1 - <u>  2² </u>  

           5³ ²

D ≅  0.99974

 

Afina-wow [57]4 years ago
7 0
I would try putting it into a graphing calculator... then you should come up with an answer


Hope this helps :)
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Answer:

i think it is 37

Step-by-step explanation:

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4 years ago
A box on a 20 degree incline is shown with vectors radiating from a point in the center of the box. The first vector points up a
Finger [1]

The images to solve this problem is in the attachment.

Answer: F_{fs} = 671.0 N; F_{N} = 300 N

Step-by-step explanation: From the image in the attachment and knowing that the box is in equilibrium, i.e., the "sum" of all the forces is 0, it is possible to conclude that:

F_{fs}  = F_{gx} and F_{N} = F_{gy}

Using trigonometry, shown in the second attachment, the values for each force are:

  • Force of Static Friction

sin 20° = \frac{F_{gx} }{F_{g} }

F_{gx} = F_{g}. sin(20)

F_{gx} = 735.0.913

F_{gx} = 671.0

  • Normal Force

cos 20° = \frac{F_{gy} }{F_{g} }

F_{gy} = F_{g}. cos (20)

F_{gy} = 735.0.408

F_{gy} = 300

The force of static friction is 671N and normal force is 300N

8 0
3 years ago
Read 2 more answers
The Leukemia and Lymphoma Society sponsors a 5K race to raise money. It receives $55 per race entry and $10,000 in donations, bu
loris [4]
Donations = $10,000
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Expense = $15 per race entry
Budget ≥ $55,000

Let x =  the number of race entries.
Total revenue = Donations + Race entries - Expenses
Therefore
10000 + 55x - 15x ≥ 55000
40x ≥ 45000
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6 0
4 years ago
There are 80 total students in the 7th grade this year and the ratio of boys to girls is 3;7. How many boys are in 7th grade thi
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5 0
3 years ago
Read 2 more answers
Suppose that a storm front is traveling at 33 mph. When the storm is 13 miles away a storm chasing van starts pursuing an averag
kramer

Answer:

= 15mins 18 seconds. The storm chaser van drove 13.53 miles to catch up with the storm which obviously has moved less than 0.53 miles as it was same time but multiplied below by 0.5 per minute as speed per minute is 0.5 for the storm. See right at the end the storm only moved 1.11 mile.

Step-by-step explanation:

We count in 1 minutes

54 mph = 54/60 = 0.9 miles per minute

Storm = 13 m +  1 minute  is;

33/60 = 0.55 miles = 11/20

M = (16 7/10 * 9/10x) = ( 3 7/10 * 11/20y ) +13

M = 15 3/10x = ( 407/200y +13)       (407/200 = y starting value +13)

M = 15 3/10x =  15 3/10 = 16 7/10x (the same as 16 7/10* 9/10 for x)

M = 15 3/10 x = 15 3/10  = 15.03    

M = 16 7/10x  / 9/10y                      (is also the same as 186/1000)

X = 185⁄1000 = 37⁄200xy x 16 7/10  (as starting value)

7/10 of 60 = 42 minutes

3/10 of 60 = 18 minutes

x = 15 mins 18 seconds.

y = 15 mins  18 seconds.

as 0.005 left over for y 3/10 was actually 15.035 gives us 0.005 of 60 can not be rounded up to a second.

However as we started with 16mins and 7/10 we can see that we multiplied by 9/10 so when we divide 16 7/10 by 9/10 we find  185⁄1000 = 37⁄200

To equal the mileage of the storm of where we multiplied 3 7/10 by 17/10

= 37/200 just the same

We added 13 miles of the storm to find each was multiplied by the larger x sum 9/10 and y was multiplied  

As 35/200 + 13 =  

13 37/200  

37/200 of 60 = 11.1 = 11.06 minutes which is

= 15.04 % more for y as 13 + 2 mins + 06 seconds = 15.06 = 15.035

The percentage looks the same but valued different as 2 of 13 as a percentage is multiplied as 13 x 15.04%  to equal the 2 of 15 miles as 15.04%.

To find how many miles we go back and see 15.035 = 15 7/200

Then we multiply this by 0.9 miles for the storm van

= 15 7/200 x 0.9 = 13.5315 = 13.53 miles

For the storm itself we can prove 0.53  increase of mileage

417/200 x 0.53 = 1.10505 = 1.11 miles. rounded up

5 0
4 years ago
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