All categories

2 years ago

16 ft

Mathematics

1 answer:

maksim [4K]2 years ago

6 0

The dimensions of the border is 1.5 feet for the garden

A rectangle is a quadrilateral with four sides and four angles in which opposite sides are equal and parallel.

The area of a rectangle = Length * breadth

Given that length of garden = 16 ft., width of garden = 12 ft.

It is surrounded by a mulch of width x, hence:

New length = 16 + x + x = 16 + 2x

New width = 12 + x + x = 12 + 2x

The area of garden = 16 + 2x(12 + 2x) = 192 + 56x + 4x²

Since the maximum area is 285 ft, hence:

192 + 56x + 4x² = 285

4x² + 56x - 93 = 0

x = 1.5 feet

The dimensions of the border is 1.5 feet

Find out more at: brainly.com/question/1501950

You might be interested in

Please help! 30 points and crown! A diagonal of a cube measures StartRoot 750 EndRoot cm. The diagonal of a face measures StartR

rodikova [14]

Let length, width, and height be s.

Then diagonal of any face would be √( s² + s² ) = √( 2s² )

And we know that it measures √( 500 ) so that's sufficient for us to figure out the length of an edge of the cube. We do not need to worry about the diagonal of the cube.

Now we have to solve √( 500 ) = √( 2s² )

Square both sides:

500 = 2s²

Divide both sides by 2:

250 = s²

Take the square root of both sides:

√(250) = s ≈ 15.8113883

Rounding to nearest tenth:

s ≈ 15.8

Final answer: 15.8

Hope this helps.

8 0

3 years ago

Read 2 more answers

Prove that 25^11−5^19 is divisible by 31.

SCORPION-xisa [38]

Answer:

Divisible by 3 is the answer

Step-by-step explanation:

First get everything to have the same base of 5

25^11 - 5^19

(5^2)^11 - 5^19

5^(2*11) - 5^19

5^22 - 5^19

Now factor out the GCF 5^19 to get

5^22 - 5^19

5^(19+3) - 5^(19+0)

5^19*5^3 - 5^19*5^0

5^19(5^3 - 5^0)

5^19(125 - 1)

5^19*(124)

At this point, we factor the 124 into 31*4 to end up with this full factorization: 5^19*31*4

Therefore, 25^11 - 5^19 is equivalent to 5^19*31*4

Since 31 is a factor of the original expression, this means the original expression is divisible by 31.

4 0

3 years ago

The sanctuary currently has 125 exotic fish. The average amount of the tank allotted for each fish is represented by the binomia

sveta [45]

Does anyone wanna help me with something ill give u bloxburg (from ro _blox) money if u know how to do it!And yes it’s math Oudh

6 0

3 years ago

18) -32.-132, -232, -332, .. Find a

Valentin [98]

Answer:

Step-by-step explanation:

next term is -432

5 0

2 years ago

On any given day, mail gets delivered by either Alice or Bob. If Alice delivers it, which happens with probability 1/4 , she doe

Troyanec [42]

Answer:

(a) The value of fₓ (9.5) is 0.125.

(b) The value of fₓ (10.5) is 0.50.

Step-by-step explanation:

Let X denote delivery time of the mail delivered by Alice and Y denote delivery time of the mail delivered by Bob.

It i provided that:

$X\sim U(9, 11)\\Y\sim U(10, 12)$

The probability that Alice delivers the mail is, p = 1/4.

The probability that Bob delivers the mail is, q = 3/4.

The probability density function of a Uniform distribution with parameters [a, b] is:

$f(x)=\left \{ {{\frac{1}{b-a};\ a, b>0} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Alice is:

$f(X_{A})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[9, 11]} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Bob is:

$f(X_{B})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[10, 12]} \atop {0;\ otherwise}} \right.$

(a)

Compute the value of fₓ (9.5) as follows:

For delivery time 9.5, only Alice can do the delivery because Bob delivers the mail in the time interval 10 to 12.

The value of fₓ (9.5) is:

$f_{X}(9.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times0)\\=\frac{1}{8}\\=0.125$

Thus, the value of fₓ (9.5) is 0.125.

(b)

Compute the value of fₓ (10.5) as follows:

For delivery time 10.5, both Alice and Bob can do the delivery because Alice's delivery time is in the interval 9 to 11 and that of Bob's is in the time interval 10 to 12.

The value of fₓ (10.5) is:

$f_{X}(10.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times\frac{1}{2})\\=\frac{1}{8}+\frac{3}{8}\\=0.50$

Thus, the value of fₓ (10.5) is 0.50.

5 0

3 years ago