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3 years ago

12

How can I express logbx-(logby+logbz) as a single log?

1 answer:

GuDViN [60]3 years ago

3 0

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\ \quad \\
% Logarithm of rationals
log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)\\\\
-----------------------------\\\\
log_b(x)-[log_b(y)+log_b(z)]\implies log_b(x)-[log_b(yz)]
\\\\\\
log_b\left( \cfrac{x}{yz} \right)$

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