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kap26 [50]
3 years ago
6

Compare using <, =, or >. –2.1 _____ –1.2

Mathematics
2 answers:
morpeh [17]3 years ago
6 0
-2.1<-1.2
hope it works

Fudgin [204]3 years ago
4 0
                                     -2.1 < -1.2 
when its negative you want it to b closest to 0 as possible
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Sam is baking cakes at her parent’s bakery. She gets paid 20 a week in addition to 5 for every cake she bakes. She made 50 this
denis-greek [22]

Answer:

i think it is 20 + 5x = 50    or  f(x)=2(3^x)

Step-by-step explanation:

equation to show how many cakes sam baked this week:

20 + 5x = 50

20 = 20 dollars

5 = 5 more dollars

x = number of cakes

therefore, sam earned $50 this week.

4 0
3 years ago
Read 2 more answers
Factor finder for 42
EastWind [94]

Answer:

-42, -21, -14, -7, -6, -3, -2, -1, 1, 2, 3, 6, 7, 14, 21, & 42

Step-by-step explanation:

5 0
3 years ago
34 + 2 ⋅ 5 = ____. (Input only whole numbers.) PLZZZ help asp
Gwar [14]
PEMDAS order refers to parentheses, exponents, multiplication, division, addition, and subtraction. So, 2*5=10 and 34+10=44.
4 0
3 years ago
Read 2 more answers
Cosx+1/sin^3x=cscx/1-cosx
ANTONII [103]
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).

 </span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).

 </span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.

 </span>
<span>I hope this helps! </span>
8 0
3 years ago
What is the greatest common factor of the pair of numbers?
geniusboy [140]
The answer is 66.
66 * 3 = 198
66 * 5 = 330
3 0
3 years ago
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