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yan [13]
3 years ago
7

Use the theoretical method to determine the probability of the following event. A randomly selected person has a birthday in Nov

ember
Mathematics
1 answer:
MakcuM [25]3 years ago
3 0

Answer:

There is an 8.22% probability that a randomly selected person has a birthday in November.

Step-by-step explanation:

The theoretical method to find the probability is the division of the number of desired outcomes by the number of total outcomes.

A randomly selected person has a birthday in November

There are 365 days in a year, so the number of total outcomes is 365.

There are 30 days in november, so the number of desired outcomes is 30.

So the probability is

P = \frac{30}{365} = 0.0822

There is an 8.22% probability that a randomly selected person has a birthday in November.

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the perimeter of a rectangle is 54 meters. one side is 3 meters less than four times the length of the other side.
Firdavs [7]
54 = 2(4x-3) + 2(x)
54 = 8x-6 + 2x
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a beauty salon buys bottles of gel for $4.50 and marks up the price by 40% for what price do they sell each bottle?
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Two sizes of cans of beans are similar. The thickness of the walls and bases are the same in both cans. The ratio of their surfa
agasfer [191]

Answer:

It costs  $0.216  to make smaller can and $0.324 to make larger can

Step-by-step explanation:

Given:

The ratio of the surface areas = 4:9

Area of smaller cans =  36 sq in

Cost  = $0.006 per square inch  

To Find:

how much does it cost to make each can = ?

Solution:

Lets the area of the larger can be x

the ratio is  4 :  9

then 4x =  9.(36)

4x = 216

x = \frac{216}{4}

x =  54

The area of the larger can is 54 sq in

Now the cost of making the smaller can  =   36 \times  0.006 = $0.216

The cost of making the Larger can = 54 \times 0.006 =$0.324

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! <br><br> What is (f/g)(x) ?
Rudiy27

Answer:   \bold{D.\ \dfrac{x+4}{x}\ where\ x \neq 0, \dfrac{2}{3}}

<u>Step-by-step explanation:</u>

f(x) = 3x² + 10x - 8

g(x) = 3x² - 2x


\dfrac{f(x)}{g(x)}=\dfrac{3x^2+10x-8}{3x^2-2x}=\dfrac{(3x-2)(x+4)}{x(3x-2)}=\dfrac{x+4}{x}

Restriction on x: the denominator cannot be equal to zero. So,

    x(3x - 2) ≠ 0  

→  x ≠ 0     and     3x - 2 ≠ 0

                             3x       ≠ 2

                               x       \neq \dfrac{2}{3}


8 0
3 years ago
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