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Doss [256]
3 years ago
15

Helpp me pleasse im going to cryy please respond asap

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0

Answer:

4

Step-by-step explanation:

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Find the greatest common factor of the following monomials.<br> 25x^5 20x^6
klio [65]
1x25=25
5x5=25

1x20=20
2x10=20
4x5=20

x^5 is the biggest you can take out of x^5 and x^6 and 5 is the biggest number you can take out of 20 and 25

5m^5
8 0
2 years ago
Is this relation A function? (a lot of points i’ll give)
Dmitry_Shevchenko [17]
The answer is A because the two points have the same value. Then it would not pass the state of the line test. your answer is A
3 0
3 years ago
Multiply.
Crank
The main rules that we use here are :

i) \sqrt{a \cdot b}=  \sqrt{a} \cdot \sqrt{b} for nonnegative values a and b.

ii) \sqrt{a} \cdot  \sqrt{a} =a.


Thus, first 'decompose' the numbers in the radicals into prime factors:

4 \sqrt{3} \cdot 10 \cdot  \sqrt{2\cdot2\cdot3}\cdot  \sqrt{2\cdot 3}\cdot  \sqrt{2}..

By rule (i) we write:

4 \sqrt{3} \cdot 10 \cdot \sqrt{2}\cdot \sqrt{2}\cdot \sqrt{\cdot3}\cdot \sqrt{2} \cdot  \sqrt{3} \cdot \sqrt{2}.

We can collect these terms as follows:

40 \sqrt{3}\cdot (\sqrt{3}\cdot \sqrt{3}) \cdot (\sqrt{2}\cdot \sqrt{2}) \cdot( \sqrt{2} \cdot \sqrt{2}), and by rule (ii) we have:

40 \sqrt{3}\cdot 3 \cdot 2 \cdot2=40\cdot12\cdot \sqrt{3}=480 \sqrt{3}.


Answer: 480 \sqrt{3}.
8 0
3 years ago
What is the equation of the line with a slope of
Fofino [41]
It should be C on a Friday
5 0
2 years ago
What is the missing justification in the proof?
nataly862011 [7]
The missing justification in the proof is
<span>B) Substitution property of equality

The expression for sin</span>² x and cos² x is substituted to the other side of the equation. Since sin x = a/c, then sin² x = a²/c². Similarly, since cos x = b/c, then cos² x = b²/c². Adding to two results to the third statement.
7 0
3 years ago
Read 2 more answers
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