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OLEGan [10]
3 years ago
5

How many proper subsets does the set T = {i, c, j, e} have?

Mathematics
1 answer:
Gala2k [10]3 years ago
5 0
Number of proper subsets = 2^number of elements- 1
= 2^n - 1
No of elements = 4
2^4-1 = 16-1 = 15
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Mike took some money to the movies. He spent 1/2 of the money on the ticket and 1/3
vivado [14]
The ticket was 5$ and the snacks was 3.33
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3 years ago
A square room has an area of 200 square feet. how long is each wall? show your work to explain why
wlad13 [49]

Answer:

about 14.142ft

Step-by-step explanation:

A square has four equal sides.

The area of a square:      length * width = area

Because you know that all of the sides are equal, you can just say:

length * length = area

Multiplying a value (in this case, length) by itself is the same thing as squaring it. So, you can simplify the equation further by writing:

length² = area

Fill in what you know:

length² = 200ft²

Now, work the problem backwards by taking the square root of 200 to find the length:

√length² = √200ft²

length = 14.142ft

So, each wall is 14.142ft long

You can test this by working the problem in reverse:

14.142ft * 14.142ft ≈ 200ft²

7 0
3 years ago
Select the correct answer.
Molodets [167]

Answer:

A.

to discuss Shays's Rebellion in Massachusetts

3 0
3 years ago
Which of the following functions is graphed below?
dalvyx [7]

Answer:

The function graphed is y = Ix - 5I - 4 ⇒ answer D

Step-by-step explanation:

* Lets explain how to solve this problem

- From the graph

# The graph intersects the x-axis at x = 1 and x = 9

∴ The x-intercepts are 1 and 9

- We can find x-intercept by equate y by 0

* Lets equate the answers by zero to find the x-intercept

# y = Ix + 5I - 4

∵ Ix + 5I - 4 = 0

- Add 4 to both sides

∴ Ix + 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix + 5I = 4

∴ x + 5 = 4 ⇒ subtract 5 from both sides

∴ x = -1

- OR

∴ x + 5 = -4 ⇒ subtract 5 from both sides

∴ x = -9

∴ The x-intercepts are -1 and -9 not the same with figure

# y = Ix - 5I + 4

∵ Ix - 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix - 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

 value is always positive

∴ We can't solve this equation

# y = Ix + 5I + 4

∵ Ix + 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix + 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

 value is always positive

∴ We can't solve this equation

# y = Ix - 5I - 4

∵ Ix - 5I - 4 = 0

- Add 4 to both sides

∴ Ix - 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix - 5I = 4

∴ x - 5 = 4 ⇒ add 5 to both sides

∴ x = 9

- OR

∴ x - 5 = -4 ⇒ add 5 to both sides

∴ x = 1

∴ The x-intercepts are 1 and 9 the same with figure

* The function graphed is y = Ix - 5I - 4

5 0
3 years ago
Some help would be great, also giving brainliest.
Harrizon [31]
The area of the shaded region would be 64m²
8 0
3 years ago
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