Answer:
The distance between zoo and library is 200 feet....
Step-by-step explanation:
Look at the picture. As the figure describes,
Let H denote the position of Helicopter.
Z denote the position of Zoo.
and L denote the position of library.
Hence, we will firstly find the distance between G and zoo and then we find the distance between G and library and subtract the first distance from second to obtain the distance between zoo and library.
In ΔHGZ.
tan 60°=HG/GZ
√3=100√3/GZ
Hence, GZ=100 feet.
Similarly in ΔHGL
tan 30°=HG/GL
1/√3=100√3/GL
GL=300 feet.
Hence, the distance between zoo and library is:
GL-GZ
=300-100
=200 feet.
Hence, the distance between zoo and library is 200 feet....
Answer:
cos x = 8/f.
Step-by-step explanation:
We can use the identity :
tan x = sin x / cos x.
Substituting:
e/8 = e/f / cos x
e/8 * cos x = e/f
cos x = e/f * 8/e
cos x = 8e / fe
cos x = 8/f.
Cubic, since it has three dimensions instead of only two.
For this case, the first thing we must do is apply the law of the sine.
We then have the following expression:
sine (65) / x = sine (104) / 36
Clearing the value of x we have:
x = (sine (65) / sine (104)) * (36)
x = 33.6 feet
Answer:
The distance between the sandbox and garden is:
x = 33.6 feet