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sp2606 [1]
4 years ago
10

PLEASE HELP ME!!!! The average temperature of Kopikoville was reported to be - 19° last year. This year, the average temperature

of Kopikoville rose by 10°. Which of the following is true about this year's average temperature of Kopikoville?
A.
This year's average temperature of Kopikoville is - 9°.
B.
This year's average temperature of Kopikoville is 29°.
C.
This year's average temperature of Kopikoville is - 29°.
D.
This year's average temperature of Kopikoville is 9°.
Mathematics
1 answer:
yawa3891 [41]4 years ago
8 0

Answer:

a

Step-by-step explanation:

idk how to explain this

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Solve the compound inequality and graph the solution
lisov135 [29]

Answer:

x ≤ -3 or 1 < x

Step-by-step explanation:

Solve an inequality the same way you would solve an equation, with one exception. If you multiply or divide by a negative number, the inequality symbol is reversed.

... x + 7 ≤ 4 . . . . . left inequality

... x ≤ -3 . . . . . . . subtract 7 to get the x-term by itself

___

... 5 - 3x < 2 . . . . right inequality

... -3x < -3 . . . . . . subtract 5 to get the x-term by itself

... x > 1 . . . . . . . . . divide by -3. Since -3 is negative, we reverse the inequality symbol

The problem statement says the solution is the OR of these, so ...

... x ≤ -3 . . or . . 1 < x

_____

These are graphed on a number line with a solid dot at -3, and an arrow to the left from there; and an open dot at +1, and an arrow to the right from there. (The dot at 1 is open because x=1 is not in the solution set.)

3 0
3 years ago
Pls help !!!!
Nuetrik [128]

Answer:

At any given moment, the red ant's coordinates may be written as (a, a) where a > 0. The  red ant's distance from the anthill is a\sqrt{2} . The black ant's coordinates may be written  as (-a, -a) and the black ant's distance from the anthill is a\sqrt{2}  . This shows that at  any given moment, both ants are  a\sqrt{2} units from the anthill.

Step-by-step explanation:

Given:

red ant's coordinates written as (a,a)

black ant's coordinates are written  as (-a, -a)

To find:

The distance of red and black ants from anthill

Solution:

Compute the distance of red ant from the anthill using distance formula

d (red ant) = \sqrt{(a-0)^{2}+ (a-0)^{2}}

                 = \sqrt{a^{2} + a^{2} }

                 = \sqrt{2a^{2} }

                 = a\sqrt{2}

So distance of red ant from anthill is a\sqrt{2}

Compute the distance of black ant from the anthill using distance formula

d (black ant) = \sqrt{(-a-0)^{2}+ (-a-0)^{2}}

                    = \sqrt{(-a)^{2} + (-a)^{2} }

                    = \sqrt{a^{2} + a^{2} }

                 = \sqrt{2a^{2} }

                 = a\sqrt{2}

So distance of black ant from anthill is a\sqrt{2}

Hence both ants are a\sqrt{2}   units from the anthill.

4 0
3 years ago
The length of a rectangle is 2 inches more than 4 times the width. The perimeter is 64 inches. Find the length and the width.
pashok25 [27]
<span>The width is 6 inches and the length is 26 inches.

Explanation:
L=4w+2, since the length is 2 more than 4 times the width.

The perimeter is given by P=2L+2w; using our equation for L, we have
P=2(4w+2)+2w.

Using the distributive property, we have
P=2*4w+2*2+2w
P=8w+4+2w.

Combining like terms, we have P=10w+4.

We know the perimeter is 64, so we have
64=10w+4.

Subtract 4 from both sides:
64-4=10w+4-4
60=10w.

Divide both sides by 10:
60/10 = 10w/10
6=w.

Substitute this into the equation for length: L=4*6+2=24+2=26</span>
5 0
3 years ago
Read 2 more answers
Using 0-9 only once to figure this out... HELP please
NeX [460]
I have no idea on D. Sorry. I hope this helps. They may not be right I didn’t quite understand the directions.

7 0
3 years ago
At a fast food restaurant, customers are asked if they want to “round up” their bill to the next highest        dollar and donat
jarptica [38.1K]

Answer:

(a) 0.1414

(b) 0.1010

Step-by-step explanation:

(a)

The density curve is rectangular in shape.

This implies that the distribution of donations is Uniform.

(b)

Compute the probability of donations at least 85 cents as follows:

P(X\geq 85)=\int\limits^{99}_{85} {\frac{1}{99-0} \, dx

                 =\frac{1}{99}\times [x]^{99}_{85}\\\\=\frac{99-85}{99}\\\\=0.1414\\\\

Thus, the proportion of donations that are at least 85 cents is 0.1414.

(b)

Compute the probability of donations between 30 and 40 cents as follows:

P(30\leq X\leq 40)=\int\limits^{40}_{30} {\frac{1}{99-0}} \, dx

                         =\frac{1}{99}\times [x]^{40}_{30}\\\\=\frac{40-30}{99}\\\\=0.1010

Thus, the probability of donations between 30 and 40 cents is 0.1010.

7 0
4 years ago
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