<h3>SOLUTION:</h3>
<u>=</u><u>)</u><u> </u><u>acceleration</u><u>:</u>
<u>=</u><u>)</u><u>velocity</u><u>/</u><u>time</u>
<u>=</u><u>)</u><u> </u><u>4</u><u>0</u><u>0</u><u>/</u><u>1</u><u>2</u><u>0</u>
<u>=</u><u>)</u><u> </u><u>1</u><u>0</u><u>/</u><u>3</u><u> </u><u>or</u><u> </u><u>3</u><u>.</u><u>3</u><u>3</u>
Answer:
60 cycles
Explanation:
The first thing we must do to solve the problem is to find how many cycles are presented in 1cm by multiplying the frequency by the base time of the
K=time base=2ms/cm=2x10-3s/cm
f=frecuency=3000s^-1
N=fk
N=(3000)(2x10^-3)=6cycles/cm
Ntot=6x10=60cycles
Answer:
Workdone = 1476 Nm
Explanation:
Given the following data;
Force = 164 N
Mass = 55kg
Distance = 9 m
To find the work done;
Workdone = force * distance
Workdone = 164 * 9
Workdone = 1476 Nm
Therefore, the work done by the force on the television set is 1476 Nm.
Divide 3500km by 3h (according to the equation v = d/t) and you get 1167km/h.