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sattari [20]
3 years ago
8

An electromagnet is a device in which moving electric charges (current) in a coil of wire create a magnet. What’s one advantage

of using electromagnets in devices?
Electromagnets have a strong, constant magnetic field.

Electromagnets are more powerful than permanent magnets.

Electromagnets don’t need a source of electricity to work.

Electromagnets can easily be turned on and off.
Physics
1 answer:
docker41 [41]3 years ago
5 0
Electromagnets have certain advantages over permanent magnets. One of the major advantage is, the amount of electric current can easily be controlled, in turn, magnetic field can be controlled. Out of all the options, option D would be the best answer.

In short, Your Answer would be option D) Electromagnets can easily be turned on and off.

Hope this helps!
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100Gw x 35ms (note: a watt is a joule per second)
Leviafan [203]

'G'  =  "giga..."  =  billion  =  10⁹

'ms'  =  "millisecond"  =  0.001 second

100 Gw = 10¹¹ watts

35 ms  =  0.035 second

100 Gw x 35 ms  =  10¹¹ watts x 0.035 second  =  3.5 x 10⁹ J

                                                                     =  3.5 G-joules
7 0
3 years ago
A force of 15 N acts upon a 3 kg block. Calculate the acceleration of the object.
alexira [117]
B
Force=Mass times acceleration
15=3x
x=5ms^2
3 0
3 years ago
a crude approximation of voice production is to consider the breathing passages and mouth to be a resonating tube closed at one
prohojiy [21]

The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be 37^oC is 367.42 Hz.

A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.

The fundamental frequency in the tube is given by

f=\frac{v_T}{4L}

where, v_T=v\sqrt{\frac{T}{273} }

Since, T=37+273 K = 310 K

v = 331 m/s

\therefore v_T=331\sqrt{\frac{310}{273} } = 352.72 \ m/s

Using this, we get:

f=\frac{352.72}{4(0.240)} \\f=367.42 \ Hz

Hence, the fundamental frequency is 367.42 Hz.

To learn more about Attention here:

brainly.com/question/14673613

#SPJ4

7 0
1 year ago
Which image shows a non renewable resources?
Radda [10]

Where are the images?!?!?

5 0
3 years ago
Read 2 more answers
A 500 kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 30 N/m. The blo
m_a_m_a [10]

Answer:

x = 0.396 m

Explanation:

The best way to solve this problem is to divide it into two parts: one for the clash of the putty with the block and another when the system (putty + block) compresses it is   spring

Data the putty has a mass m1 and velocity vo1, the block has a mass m2 .  t's start using the moment to find the system speed.

Let's form a system consisting of putty and block; For this system the forces during the crash are internal and the moment is preserved. Let's write the moment before the crash

    p₀ = m1 v₀₁

Moment after shock

    p_{f} = (m1 + m2) v_{f}

   p₀ = p_{f}

   m1 v₀₁ = (m1 + m2) v_{f}

  v_{f} = v₀₁ m1 / (m1 + m2)

   v_{f}= 4.4 600 / (600 + 500)

  v_{f} = 2.4 m / s

With this speed the putty + block system compresses the spring, let's use energy conservation for this second part, write the mechanical energy before and after compressing the spring

Before compressing the spring

   Em₀ = K = ½ (m1 + m2) v_{f}²

After compressing the spring

   E_{mf} = Ke = ½ k x²

As there is no rubbing the energy is conserved

   Em₀ = E_{mf}

   ½ (m1 + m2) v_{f}² = = ½ k x²

   x = v_{f} √ (k / (m1 + m2))

   x = 2.4 √ (11/3000)

   x = 0.396 m

7 0
3 years ago
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