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2 years ago

I NEED HELP ON THIS SO CROWN FOR ANSWER

Mathematics

1 answer:

garri49 [273]2 years ago

4 0

Answer:

Step-by-step explanation:

16oz is one pound and the puppy is already 514 so not it's

514.5(decimal)

$514\frac{1}{2}$ (fraction)

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The temperature was –15⁰F and decreased by 10⁰ F. Which statement represents the resulting temperature in degrees Fahrenheit?

Alex_Xolod [135]

Answer:

its B -15 - 10 = -25

Step-by-step explanation:

8 0

3 years ago

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

$\log_dabc=\log_da+\log_db+\log_dc$

Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

$\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}$

so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

Similarly,

$\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}$

so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

$\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}$

###

Another way to do this:

$\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}$

$\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}$

$\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12$

Then

$abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}$

So we have

$\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}$

4 0

2 years ago

Three red and three blue flags are arranged randomly along

laiz [17]

$|\Omega|=\dfrac{6!}{3!3!}=\dfrac{4\cdot5\cdot6}{2\cdot3}=20\\A=\{RBRBRB,BRBRBR\}\\|A|=2\\\\P(A)=\dfrac{2}{20}=\dfrac{1}{10}$

3 0

2 years ago

Read 2 more answers

Morgan earned $70.00 at her job when she worked for 4 hours. How much money did she earn each hour?

Mila [183]

Answer:

divide the 70.00 by the four hours

Step-by-step explanation:

4 0

2 years ago

explain how the singular forms of morning, night, monday, and tuesday may be changed to the plural forms every-morning every-nig

Rus_ich [418]

Besides using the word "every" before the singular forms of the words above, they can also be changed to their plural forms by adding "s" behind them. For example "morning" becomes "mornings".

<h3>

Plural form of Morning in a Sentence</h3>

He works mornings. or
Mornings, I like to exercise.

Other examples related to the words above are:

The Tuesdays in March are going to be very busy.
The nights I spent on the voyage was blissful.

See the link below for more about the Plural forms:

brainly.com/question/586494

5 0

1 year ago