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lawyer [7]
3 years ago
7

1/3 *divide* 3/8 = m help?

Mathematics
2 answers:
MariettaO [177]3 years ago
5 0

Answer:

8/9

Step-by-step explanation:

To make it a fraction form answer, you multiply the dividend numerator by the divisor denominator to make a new numerator.

Furthermore, you multiply the dividend denominator by the divisor numerator to make a new denominator:

'

Thus, the answer to 1/3 divided by 3/8 in fraction form is: 8/9

Alik [6]3 years ago
5 0

Answer:

8/9

Step-by-step explanation:

Use a calculator. It is way easier. Math is hard.

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214 out of 450 students went to a concert, what percent did not go?
Vera_Pavlovna [14]

Answer:

.75% .0075 of the people that went to the concert said they would go if they could not see the band again. To find this you simply divide 9 by 1200, which equals .0075

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
6. Which expression is equivalent to -21 + 28x?
Rina8888 [55]
Solution,
-28x^2+35x
take the common,
-7x(4x-5)
The answer is -7x(4x-5)
Here,
If we solve,
-7x(4x-5)
Then, the answer would be:
= -7x*4x+7x*5
= -28x^2+35x
Hope it helps
Good luck on your assignment
3 0
3 years ago
Rashida brought three tickets to a concert for $75 at this rate how much would 5 tickets cost
Wittaler [7]

 In order for you to understand this question you have to know what the unit rate is. In order to find it you divide 75 by 3  which is 25 so you know that 1 ticket will cost 25$ so then you multiply that 25 times 5 to get your final answer which is 125.

7 0
3 years ago
Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the
zlopas [31]

Answer:

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}

\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

3 0
3 years ago
How do I solve for the missing lengths?
Advocard [28]

Answer:

Part 4) ER=3\ units

Part 5) DF=9\sqrt{10}\ units

Part 6) DE=30\ units

Step-by-step explanation:

Part 4) Find ER

we know that

In the right triangle ERF

Applying the Pythagorean Theorem

EF^2=ER^2+RF^2

substitute the given values

(3\sqrt{10})^2=ER^2+9^2

solve for ER

ER^2=(3\sqrt{10})^2-9^2

ER^2=90-81\\ER^2=9\\ER=3\ units

Part 5) Find DF

we know that

In the right triangle DRF

Applying the Pythagorean Theorem

DF^2=DR^2+RF^2

substitute the given values

DF^2=27^2+9^2

DF^2=810\\DF=\sqrt{810}\ units

simplify

DF=9\sqrt{10}\ units

Part 6) Find DE

we know that

DE=DR+RE ----> by segment addition postulate

we have

DR=27\ units\\RE=ER=3\ units

substitute

DE=27+3=30\ units

3 0
2 years ago
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