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3 years ago

I just need help with these few questions... please give me actual answers.

Mathematics

2 answers:

mario62 [17]3 years ago

8 0

Answer:

Step-by-step explanation:

1. -7 = w + 5

w = -12

(-12 + 5 = -7)

2. -4p + 38 = 10

-38 -38

-4p = -28

/-4 /-4

p = 7

3. -3 1/2 = -1 1/4b

/1.25 /1.25

-2 4/5 = -b

2 4/5 = b

2.8 = b

Gelneren [198K]3 years ago

7 0

Answer:

Step-by-step explanation:

Question 1:

-7 = w + 5

- 5 - 5

-12 = w

w = -12

Question 2:

-4p + 38 = 10

- 38 - 38

-4p = -28

----- ----- fraction bar... -4p divided by -4, -28 divided by -4

-4 -4

p = 7

Question 3:

-3 1/2 = -1 1/4b

- 7 = - 5

----- ----- b

2 4

4 -7 -5 4

---- x ----- = ------ x ----- b

-5 2 4 -5

-28

---- = b

-10

-28 2 14

----- divided by ---- = -----

-10 2 5

b = 2 4/5

hope this helps !

mark me brainliest :D

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Answer:

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Step-by-step explanation:

Let ∠1 = x

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If a coin is tossed three times, find probability of getting

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${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

‣ A coin is tossed three times.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

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${\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}$

$\star \: \tt P(E)= {\underline{\boxed{\sf{\red{ \dfrac{ Favourable \: outcomes }{Total \: outcomes} }}}}}$

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes $\tt [ \: n(s) \: ]$ = 8

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Here

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Here

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• Total outcomes = 8

$\longrightarrow \sf Probability_{(at \: least \: 2 \: tails)} = \dfrac{4}{8}$

$\therefore \sf Probability_{(at \: least \: 2 \: tails)} = \orange{\dfrac{1}{2}}$

4) Exactly 2 heads 

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 2 \: heads)} = \pink{ \dfrac{3}{8}}$

5) Exactly 3 heads

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$\therefore \sf Probability_{(exactly \: 3 \: heads)} = \purple{ \dfrac{1}{8}}$

$\rule{280pt}{2pt}$

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