A ball is dropped from a 32-foot wall. Each time it bounces, it rises half as high as the distance it fell. The ball is caught w
2 answers:
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7)
Given the line
We know that the slope-intercept form of the line equation is
here
m is the slope and b is the intercept
Thus, the slope = -1
We know that the parallel lines have the same. Thus, the slope of the parallel line is: -1
Using point-slope of the line equation
substituting the values m = -1 and the point (4, 0)
Writing in the slope-intercept form
Thus, the slope-intercept form of the equation of the line equation parallel to y=-x+ 2 will be:
8)
<em>Note: </em><em>Your line is a little bit unclear. But, I am assuming the</em>
<em>ine is: </em>y = -x-1
<em />
Given the assumed line
y = -x-1
We know that the slope-intercept form of the line equation is
here
m is the slope and b is the intercept
Thus, the slope = m = -1
We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:
slope = m = -1
perpendicular slope = – 1/m = -1/-1 = 1
Using point-slope of the line equation
substituting the values m = 1 and the point (4, 3)
Writing in the slope-intercept form
y-3 = x-4
y = x-4+3
y = x - 1
Thus, the slope-intercept form of the equation of the line equation perpendicular to y = -x-1 will be:
- y = x - 1
Answer:
The length of the diagonal of the cube = √(3 × 10²) = √300 cm
Step-by-step explanation:
* Lets revise the properties of the cube
- It has six equal faces all of them are squares
- It has 12 vertices
- The diagonal of the cube is the line joining two vertices in opposite
faces (look to the attached figure)
- To find the length of the diagonal do that:
# Find the diagonal of the base using Pythagoras theorem
∵ The length of the side of the cube is L
∵ The base is a square
∴ The length of the diagonal d = √(L² + L²) = √(2L²)
- Now use the diagonal of the base and a side of a side face to find the
diagonal of the cube by Pythagoras theorem
∵ d = √(2L²)
∵ The length of the side of the square = L
∴ The length of the diagonal of the cube = √[d² + L²]
∵ d² = [√(2L²)]² = 2L² ⇒ power 2 canceled the square root
∴ The length of the diagonal of the cube = √[2L² + L²] = √(3L²)
* Now lets solve the problem
∵ The length of the side of the square = 10 cm
∴ The length of the diagonal of the cube = √(3 × 10²) = √300 cm
- Note: you can find the length of the diagonal of any cube using
this rule Diagonal = √(3L²)
