Mr. Munoz gave his students the following expression to simplify as their exit ticket for class one day.
1 answer:
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Answer:
OD = 9.375"
Step-by-step explanation:
We can draw a line from O to B to create a triangle.
Then, Triangle ODB and Triangle ACB are similar, so their corresponding side's ratio are similar as well.
Triangle ACB, we can use pythagorean theorem to figure out CB:
AC^2 + CB^2 = AB^2
15^2 + CB^2 = 17^2
225 + CB^2 = 289
CB^2 = 64
CB = 8
Now relating the corresponding sides, we can figure out OD:
Answer:
17.5%
Step-by-step explanation:
First of all, see this situation as a cumulative binomial distribution. You have isolated trials with a probability of success. This makes it binomial. The wording of the question "what is the probability of at least half..." makes this cumulative.
There are a few ways to calculate this, and I'm not quite sure which way you're familiar with. I'll show the cumbersome way and use wolfram to make the calculation.
First, I'll calculate the probability for 15 success, given 30 trials.
30c15*0.4^15*0.6^15
Since the question asks for the probability of at least 15 success, I'll have to make a calculation for the probability of 16 successes, then 17, and so on. Then I'll have to add all the probabilities together. So, I'll use wolfram for that (see attached)
