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Genrish500 [490]
4 years ago
14

Write the product as a mixed number 5 x 3/10

Mathematics
1 answer:
Citrus2011 [14]4 years ago
5 0
1 1/2 is the mixed number so yeah have a very good rest of your day
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How much is it 2 5/6-1/8<br> Explain:
labwork [276]
Ur mom cuz its called ask google or think bub
3 0
3 years ago
Complete each trinomial such that it can be rewritten in the form
lukranit [14]

Answer:

Step-by-step explanation:

1.5x^2+6x+.... so that it can be rewritten in the form a(x+b)^2

Let .... be C

1.5x^2+6x+C

=1.5(x^2+4x+(C/1.5))

Compare above with 1.5(x+2)^2 = 1.5(x^2+4x+4)

C/1.5=4

C=6

So the expression should be 1.5x^2+6x+6

It can be rewritten to 1.5(x+2)^2

8 0
2 years ago
The probability of winning on an arcade game is 0.568. If you play the arcade game 22 times, what is the probability of winning
Serggg [28]

The probability of winning 15 out of the 22 games is P = 0.099

<h3>what is the probability of winning more than 15 times?</h3>

We know that the probability of winning on the arcade game is 0.568.

Then the probability of losing is:

P = 1 - 0.568 = 0.432

The probability of winning 15 out of 22 games is given by the equation:

P = C(22, 15)*(0.568)^{15}*(0.432)^{7}

Where C(22, 15) is the number of combinations of 15 elements that we can make with a set of 22 elements, given by:

C(22, 15) = \frac{22!}{(22 - 15)!*15!}  = \frac{22!}{7!*15!} = \frac{22*21*20*19*18*17*16}{7*6*5*4*3*2*1} = 170,544

Then the probability is:

P = 170,544*(0.568)^{15}*(0.432)^7 = 0.099

If you want to learn more about probability:

brainly.com/question/25870256

#SPJ1

8 0
2 years ago
Max constructed a scale model of the Eiffel tower. The base area of the model is 0.25 square meters, while the base area of the
Vanyuwa [196]

Answer:

1:250

Step-by-step explanation:

\sqrt{15625/0.25}

=\sqrt{62500}

=250

8 0
4 years ago
What is the area of the hexagon below to the nearest tenth of a square centimeter?
Svet_ta [14]

Answer:120x10 1200 half a piece = 60% 50-60=10%=1200

Step-by-step explanation:

5 0
3 years ago
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