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Tamiku [17]
2 years ago
7

(f) A recipe calls for 1 1/2 cups of flour, 3/4 cup of white sugar, and 1/8 cup of brown sugar.

Mathematics
2 answers:
V125BC [204]2 years ago
7 0

Answer:

a) 19/8

b) 3 cup since it's 2.4

FinnZ [79.3K]2 years ago
6 0

Answer:

grade 11 po to Bread and pastry Production

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<h3>The answer is D.</h3>

Step-by-step explanation:

Explanation:

The rule of a triangle is that it the other two sides could not be longer than longest side of the triangle. If the two sides added up together is greater than the longest side, the triangle would no longer be connected. Since 8 + 12 ft still works for the longest side of the triangle, it will be considered the length of the third side.

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List five numbers that have 3,5 and 7 as prime factors
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<span>Its: 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23 </span>
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if two points are givin, then exactly one line can be drawn through those two points. which geomerty trem does the statement rep
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the correct answer is

Step-by-step explanation:

hope this helps u!!

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2 years ago
4<br><img src="https://tex.z-dn.net/?f=4x%20-%203%20%3D%202x%20%2B%207%20find%20x%20" id="TexFormula1" title="4x - 3 = 2x + 7 fi
natima [27]

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x=5

Step-by-step explanation:

That is your answer .

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4x-2x=2x+10-2x

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2x=10

divide both sides by 2 2x/2=10/2

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Hope this helps :)

4 0
3 years ago
An article in The Engineer (Redesign for Suspect Wiring," June 1990) reported the results of an investigation into wiring errors
GarryVolchara [31]

Answer:

a) The 99% confidence interval on the proportion of aircraft that have such wiring errors is (0.0005, 0.0095).

b) A sample of 408 is required.

c) A sample of 20465 is required.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Of 1600 randomly selected aircraft, eight were found to have wiring errors that could display incorrect information to the flight crew.

This means that n = 1600, \pi = \frac{8}{1600} = 0.005

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.005 - 2.575\sqrt{\frac{0.005*0.995}{1600}} = 0.0005

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.005 + 2.575\sqrt{\frac{0.005*0.995}{1600}} = 0.0095

The 99% confidence interval on the proportion of aircraft that have such wiring errors is (0.0005, 0.0095).

b. Suppose we use the information in this example to provide a preliminary estimate of p. How large a sample would be required to produce an estimate of p that we are 99% confident differs from the true value by at most 0.009?

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

A sample of n is required, and n is found for M = 0.009. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.009 = 2.575\sqrt{\frac{0.005*0.995}{n}}

0.009\sqrt{n} = 2.575\sqrt{0.005*0.995}

\sqrt{n} = \frac{2.575\sqrt{0.005*0.995}}{0.009}

(\sqrt{n})^2 = (\frac{2.575\sqrt{0.005*0.995}}{0.009})^2

n = 407.3

Rounding up:

A sample of 408 is required.

c. Suppose we did not have a preliminary estimate of p. How large a sample would be required if we wanted to be at least 99% confident that the sample proportion differs from the true proportion by at most 0.009 regardless of the true value of p?

Since we have no estimate, we use \pi = 0.5

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.009 = 2.575\sqrt{\frac{0.5*0.5}{n}}

0.009\sqrt{n} = 2.575*0.5

\sqrt{n} = \frac{2.575*0.5}{0.009}

(\sqrt{n})^2 = (\frac{2.575*0.5}{0.009})^2

n = 20464.9

Rounding up:

A sample of 20465 is required.

8 0
2 years ago
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