Answer #1:
the difference between the PARIMITER and AREA of a shape is
- PARIMITER is the length of all sides in total
- AREA is the square ore cubic measurement aka VOLUME of a shape
Answer #2:
the difference between 1in and 2in is 1 in
Step-by-step explanation:
#1:
say we have a square that is 2 by 3 units, to measure the shape in both mediums we will use two easy functions
~ PARIMITER = 10
to figure out the outside edge of this shape, we need to measure all single sides and add them together
(2 + 2) + (3 + 3) = 4 + 6 = 10
^ note: be sure to add BOTH sides even if they have same measurements, beings there are two sides that have a measurement of 2 units, we add them together, same with the sides of 3, then we add those together
~ AREA = 6
to find the area, we just need to take ONE of each axis side (ei only left or right, top or bottum, and in some cases front or back) and lay them as shown
width = 2
height = 3
then we multiply them with each other
2 * 3 = 6
#2
finding the difference between two numbers can be quite easy, all we do is subtract 1 from the other, and depending on the result, we can tell whats greater, lesser or indifferent, take a look here
say we subtract 2in from 1in
2in - 1in = 1in
we are left with 1in from the 2in, meaning that 2in is greater then 1in by 1in, HOWEVER if we subtract 2in from 1in
1in - 2in = (-1in)
the number is in the negative, meaning that there is 1in LESS in 1in then in 2in
NOTE sometimes we find out that one of has no difference or is the same as the other number, heres an example
3in - 3in = 0in
this equation represents that the first 3in is no greater, nor lesser then the second 3in, meaning both values are the same
PS: for real though i know these are easy questions but i figured id earn the crown hehe :3, feel free to fact check this if you want, and if you want to use this as foot notes for your work
, you have the remainder term approaching 
, so the horizontal asymptote is the line 
.